An object moving vertically is at the given heights at the specified times. Find the position equation s = 1/2at2 + v0t + s0 for the object. At t = 1 second, s = 193 feet At t = 2 seconds, s = 145 feet At t = 3 seconds, s = 65 feet

An object moving vertically is at the given heights at the specified times. Find the position equation s = 1/2at2 + v0t + s0 for the object. At t = 1 second, s = 193 feet At t = 2 seconds, s = 145 feet At t = 3 seconds, s = 65 feet

Name: An object moving vertically is at the given heights at the specified t
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Description: An object moving vertically is at the given heights at the specified times. Find the position equation s = 1/2at2 + v0t + s0 for the object.At t = 1 second, s = 193 feetAt t = 2 seconds, s = 145 feetAt t = 3 seconds, s = 65 feet So, s= ?

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter1: Introduction And Vectors

Section: Chapter Questions

Problem 51P: A person going for a walk follows the path shown in Figure P1.51. The total trip consists of four...

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An object moving vertically is at the given heights at the specified times. Find the position equation

s = 1/2at² + v₀t + s₀

for the object.

t = 1 second, s = 193 feet

t = 2 seconds, s = 145 feet

t = 3 seconds, s = 65 feet

So, s= ?

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