Answered: An object moves on the negative x axis…

Name: Gdocs.google.com &An object moves on the negative xaxis a distance of
Uploaded: 2024-03-05T11:56:34.000Z
Channel: Bartleby
Description: Gdocs.google.com &An object moves on the negative xaxis a distance of (5m) according tothe formula (x= -7t +2t^2), the time it* :takes is equal tothe formula (X= -7t + 2t²)2s4s2.5s O3.5s

Science

Physics

An object moves on the negative x axis a distance of (5m) according to the formula (x= -7t +2t^2), the time it :takes is equal to the formula (X= -7t + 2t²) 2s 4s 2.5s 3.5s

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter1: Units And Measurement

Section: Chapter Questions

Problem 82AP: (a) A car speedometer has a 5% uncertainty. What is the range of possible speeds when it reads 90...

See similar textbooks

Similar questions

(a) Use the distance and velocity data in Figure 3.64 to find the rate of expansion as a function of distance. (b) If you extrapolate back in time, how long ago would all of the galaxies have been at approximately the same position? The two parts of this problem give you some idea of how the Hubble constant for universal expansion and the time back to the Big Bang are determined, respectively. Figure 3.64 Five galaxies on a straight line, showing their distances and velocities relative to the Milky Way (MW) Galaxy. The distances are in millions of light years (Mly), where a light year is the distance light travels in one year. The velocities are nearly proportional to the distances. The sizes of the galaxies are greatly exaggerated; an average galaxy is about 0.1 MlY across.
A landscape architect is planning an artificial waterfall in a city park. Water flowing at 1.70 m/s will leave the end of a horizontal channel at the top of a vertical wall h = 2.35 m high, and from there it will fall into a pool (Fig. P3.42). (a) Will the space behind the waterfall be wide enough for a pedestrian walkway? (b) To sell her plan to the city council, the architect wants to build a model to standard scale, which is one-twelfth actual size. How fast should the water flow in the channel in the model? Figure P3.42
A pirate has buried his treasure on an island with five trees located at the points (30.0 m, 20.0 m), (60.0 m, 80.0 m), (10.0 m, 10.0 m), (40.0 m, 30.0 m), and (70.0 m, 60.0 m), all measured relative to some origin, as shown in Figure P1.69. His ships log instructs you to start at tree A and move toward tree B, but to cover only one-half the distance between A and B. Then move toward tree C, covering one-third the distance between your current location and C. Next move toward tree D, covering one-fourth the distance between where you are and D. Finally move toward tree E, covering one-fifth the distance between you and E, stop, and dig. (a) Assume you have correctly determined the order in which the pirate labeled the trees as A, B, C, D, and E as shown in the figure. What are the coordinates of the point where his treasure is buried? (b) What If? What if you do not really know the way the pirate labeled the trees? What would happen to the answer if you rearranged the order of the trees, for instance, to B (30 m, 20 m), A (60 m, 80 m), E (10 m, 10 m), C (40 m, 30 m), and D (70 m, 60 m)? State reasoning to show that the answer does not depend on the order in which the trees are labeled. Figure 1.69
After a ball rolls off the edge of a horizontal table at time t = 0, its velocity as a function of time is given by v=1.2i9.8tj where v is in meters per second and t is in seconds. The balls displacement away from the edge of the table, during the time interval of 0.380 s for which the ball is in flight, is given by r=00.3803vdt To perform the integral, you can use the calculus theorem [A+Bf(x)]dx=Adx+Bf(x)dx You can think of the units and unit vectors as constants, represented by A and B. Perform the integration to calculate the displacement of the ball from the edge of the table at 0.380 s.
A car is traveling at a speed of 33 m/s. (a) What is its speed in kilometers per hour? (b) Is it exceeding the 90 km/h speed limit?
A surveyor measures the distance across a straight river by the following method: starting directly across from a tree on the opposite bank, he walks x = 1.00 102 m along the riverbank to establish a baseline. Then he sights across to the tree. The angle from his baseline lo the tree is = 35.0 (Fig. P1.53). How wide is the river? Figure P1.53
(a) A car speedometer has a 5% uncertainty. What is the range of possible speeds when it reads 90 km/h? (b) Convert this range to miles per how. Note 1 km = 0.6214 mi.
Bacteria move back and f01th by using their flagella (Structures that look like little tails). Speeds of up to 50m/s(50106m/s) have been observed. The total distance traveled by a bacterium is large for its size, while its displacement is small. Why is this?
Explain why, when defining the length of a rod, it is necessary to specify that the positions of the ends of the rod are to be measured simultaneously.
Quadratic Equation: x = -6±yb²–4ac 2a AT = i; – ão Vave., drot. At dave.,e Save. || At At Vx = V0x + agt Ax Vont + at? = vox + 2a,Ax Ax (vor + Va)t '0x 1) Wile E. Coyote happens to be chasing after the Roadrunner, who is traveling in the +x-direction with a constant velocity of 8.72 m/s. Wile E. Coyote has a velocity of +3.28 m/s and a constant acceleration of +2.30 m/s? at the moment it is 10.0 m behind the Roadrunner. Take the initial position of the Roadrunner to be the origin (x = 0). a) time. Hint: Your answer should look like xR = fR(t). Express the final position of the Roadrunner (with respect to the origin) as a function of b) time. Hint: Again, your answer should look like xc = Express the final position of Wile E. Coyote (with respect to the origin) as a function of fc(t). c) use the quadratic formula here, you should get two times. Consider which one, if both, of these times makes sense in the context of this problem. How much time elapses before Wile E. Coyote catches the…
Alishba wakes up late and runs to school, covering a distance of 2.55 km in a direction of [N200 E] as measured from her home. She then realizes that her friend Lydia has her homework and races over to his house 0.5 km away [W] from the school. The two friends then decide it’s not worth going to class late so they go off to the mall that is 2.8 km [W500 S]. a) What is Alishba’s total displacement? b) If the total time taken by Alishba to run to school then over to the friend’s house was 25 minutes, what was her average velocity?
274 After slapping the burglar in the Tondo, Rodrigo ran to a nearby hut which is s = (300+) meters from 100 where he slapped the burglar. He then ran towards the hut covering a distance defined by the function s = 1.25t-0.35 – 3t3 cos(-5t) + 0.25t4e0.5t, where s is expressed in meters, t is time in seconds, and the angles are in radians. Unfortunately, 500 milliseconds after he started to ran, Berto, came in where Rodrigo slapped the burglar, saw him escaping and chased after him with a velocity defined by the v-t curve below. 1. Was Berto able to capture Rodrigo? Explain. 2. Determine the velocity and acceleration of Berto and Rodrigo 3 seconds after Rodrigo started to ran. 3. Draw the s-t and a-t curves for Berto's motion t (s) 2 3 240 220 200 180 160 140 120 100 80 60 40 20 (s/w) A