An industrial load consumes P = 25 kW with a power factor PF = 0.8 lagging. The motor in 2a is connected in parallel for power factor correction purposes: (i) Define power factor. (ii) Find the real and reactive power of the integrated system. (iii) Find the power factor of the integrated system. (iv) Explain how excitation control can be used for power factor correction, and describe how this technique could be used to reach unity power factor of the integrated system. (v) How do companies benefit from power factor correction?

An industrial load consumes P = 25 kW with a power factor PF = 0.8 lagging. The motor in 2a is connected in parallel for power factor correction purposes: (i) Define power factor. (ii) Find the real and reactive power of the integrated system. (iii) Find the power factor of the integrated system. (iv) Explain how excitation control can be used for power factor correction, and describe how this technique could be used to reach unity power factor of the integrated system. (v) How do companies benefit from power factor correction?

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter12: Power System Controls

Section: Chapter Questions

Problem 12.4P

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