An HSS 6 x 4 x 5/16 braced section (46 ksi steel) shown in Figure below is applied by a dead load of 40 k and a live load of 50 k. Check the column adequacy.
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- Situation 1: A W8x31 simply supported beam carries a uniformly distributed load. The properties of the section relevant to the problem are as follow: Use A50 steel and Cb - 1.14 d=203 mm bf = 203 mm tf-11.0 mm tw = 7.24 mm kdes - 21.1 mm ry = 51.3 mm Ix = 45.8 x 10^6 mm^4 ly- 15.4 x 10^6 mm^4 Sx-451 x 10^3 mm^3 Zx = 498 x 10^3 mm^3 J-223 x 10^3 mm^3 Cw-142 x 10^9 mm^6 1. Which of the following nearly gives the maximum safe uniform load (Wu) that the beam could carry if the span of the beam is 5m? Neglect weight of the beam. 46 KN/m 41 KN/m 51 KN/m 33 KN/mDetermine the force of the members for the space truss shown in the figure. Joints A and B are supported by ball-and-socket while Joint C is supported by short link along z-axis. Indicate whether member is tension (T) or compression (C). 2m y Sm Az By BX Bz PAR Ax CSXScanned with Ca canner a SISU KN 15m 1 2117Situation 3: A W12x22 simply supported beam carries a uniformly distributed load. The properties of the section relevant to the problem are as follow: Use A50 steel and Cb - 1.14 d=312 mm bf - 102 mm tf 10.8 mm tw = 6.60 mm kdes 18.4 mm ry-21.5 mm Ix- 64.5 x 10^6 mm^4 ly- 1.94 x 10^6 mm^4 Sx416 x 10^3 mm^3 Zx 480 x 10^3 mm^3 J-122 x 10^3 mm^3 Cw-44.0 x 10^9 mm^6 1. Which of the following nearly gives the Design Strength Moment (LRFD) if the span of the beam is 2.5m? 89 KN-m O 114 KN-m O 123 KN-m O 101 KN-m
- Q2) The members of the truss structure shown below is plain concrete. The compressive strength of the concrete is 25 MPa. Compute the maximum load P that can be carried by the structure. (Cross section of each member of the truss is 200 x 200 mm and don't use material factors and do not consider slenderness) Comment on your results briefly. P A& 2m SC 2 m 1380 2m DAW 12 x 65 column section shown in the figure is pinned at each end and has an additional support in the weak direction at a point 4.1 m from the top. Use X- 4.8 m K 1 for both directions. X+Y Properties of W 12 x 65 A 12323 mm2 - 134.11 mm ry 76.71 mm Fy- 248 MPa Determine the allowable compressive strength (kN).Problem 4: Use A992 steel and select a W shape. The service dead load is 142 kips, and the service live load is 356 kips. ↑ a 10' wwww Do wwwwww y-axis 16' x-axis
- Question 12 A W12x79 of A573 Grade 60 (Fy 415 MPa) steel is used as a compression member. It is 6 m long, fixed at the top and bottom, and has additional support in the weak direction at mid-height. Properties of the section are as follows: A = 14,500 mm^2 Iy = 258.6 x 10^6 mm^4 Iy = 84.375 x 10^6 mm^4 Calculate the critical slenderness ratio with respect to weak axis buckling using theoretical value of k.A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom with additional lateral support at mid height in the weak direction. The properties are as follows: Ag = 14,500 sq.mm, Ix= 258.6 x10^6 mm ^4 Iy=84.375 x 10^6 mm^4. 58. Calculate the nominal axial strength of the column in KNA W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom with additional lateral support at mid height in the weak direction. The properties are as follows: Ag = 14,500 sq.mm, Ix= 258.6 x10^6 mm ^4 Iy=84.375 x 10^6 mm^4. 57. Calculate the flexural buckling stress Fcr in MPa
- A W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom with additional lateral support at mid height in the weak direction. The properties are as follows: Ag = 14,500 sq.mm, Ix= 258.6 x10^6 mm ^4 Iy=84.375 x 10^6 mm^4. 56. Calculate the critical slenderness ratio with buckling about weak axisA W12x79 of A573 Grade 60 (Fy = 415 MPa) steel is used as a compression member. It is 8 m long, pinned at the top fixed at bottom with additional lateral support at mid height in the weak direction. The properties are as follows: Ag = 14,500 sq.mm, Ix= 258.6 x10^6 mm ^4 Iy=84.375 x 10^6 mm^4. 55. calculate the critical slenderness ratio with buckling about strong axis.A built-up section shown, 30 feet long, is fixed at both ends and braced in the weak direction at the midheight. A992 steel is used. Determine the following: 11. Ix 12. Ky 13. effective slenderness ratio 14. Fe 15. LRFD design strength 16. ASD allowable strength 18 4 W10 × 49 A 14.4 in² bf 10 in d. 10 in tw 0.340 in tf 0.560 in Ix= 272 in¹ Iy=93 4in¹ W10×54 A 15-3 in² bf 10 in d = 10 lin tw0-370 in tf 0.615 in Ix= 303 in 4 Ty = 103 in 1