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An experiment is conducted to determine whether intensive tutoring (covering a great deal of material in a fixed amount of time) is more effective than paced tutoring (covering less material in the same amount of time). Two randomly chosen groups are tutored separately and then administered proficiency tests. The data collected and summarized below: Group1 (the intensive group) consisted of 12 students and resulted in an average grade of 46.31 with a standard deviation of 6.44. group 2 (the paced group) consisted of 10 students and resulted in an average grade of 42.79 with a standard deviation of 7.52. Assume that the population variances of both groups are different. To test the claim that intensive tutoring is more effective than paced tutoring, find the degree of freedom and the critical value , and make a decision. df= 17 t critical value to 05 = 1.739 Fail to reject HO. df= 17 t critical value to 05 = 1.782 Fail to reject HO. df= 17 t critical value to.025 = 1.986 Fail to reject HO. df= 17 t critical value to.025 = 1.986 Reject H0. df= 17 t critical value to.05 = 1.739 Reject HO.

An experiment is conducted to determine whether intensive tutoring (covering a great deal of material in a fixed amount of time) is more effective than paced tutoring (covering less material in the same amount of time). Two randomly chosen groups are tutored separately and then administered proficiency tests. The data collected and summarized below: Group1 (the intensive group) consisted of 12 students and resulted in an average grade of 46.31 with a standard deviation of 6.44. group 2 (the paced group) consisted of 10 students and resulted in an average grade of 42.79 with a standard deviation of 7.52. Assume that the population variances of both groups are different. To test the claim that intensive tutoring is more effective than paced tutoring, find the degree of freedom and the critical value , and make a decision. df= 17 t critical value to 05 = 1.739 Fail to reject HO. df= 17 t critical value to 05 = 1.782 Fail to reject HO. df= 17 t critical value to.025 = 1.986 Fail to reject HO. df= 17 t critical value to.025 = 1.986 Reject H0. df= 17 t critical value to.05 = 1.739 Reject HO.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.5: Comparing Sets Of Data
Problem 13PPS
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An experiment is conducted to determine whether intensive tutoring (covering a great deal of material in a fixed amount of time) is more effective than paced tutoring (covering less material in the same amount of time). Two randomly chosen groups are tutored separately and then administered proficiency tests. The data collected and summarized below: Group1 (the intensive group) consisted of 12 students and resulted in an average grade of 46.31 with a standard deviation of 6.44. group 2 (the paced group) consisted of 10 students and resulted in an average grade of 42.79 with a standard deviation of 7.52. Assume that the population variances of both groups are different. To test the claim that intensive tutoring is more effective than paced tutoring, find the degree of freedom and the critical value , and make a decision. df= 17 t critical value to 05 = 1.739 Fail to reject HO. df= 17 t critical value to 05 = 1.782 Fail to reject HO. df= 17 t critical value to.025 = 1.986 Fail to reject HO. df= 17 t critical value to.025 = 1.986 Reject H0. df= 17 t critical value to.05 = 1.739 Reject HO.
Transcribed Image Text:An experiment is conducted to determine whether intensive tutoring (covering a great deal of material in a fixed amount of time) is more effective than paced tutoring (covering less material in the same amount of time). Two randomly chosen groups are tutored separately and then administered proficiency tests. The data collected and summarized below: Group1 (the intensive group) consisted of 12 students and resulted in an average grade of 46.31 with a standard deviation of 6.44. group 2 (the paced group) consisted of 10 students and resulted in an average grade of 42.79 with a standard deviation of 7.52. Assume that the population variances of both groups are different. To test the claim that intensive tutoring is more effective than paced tutoring, find the degree of freedom and the critical value , and make a decision. df= 17 t critical value to 05 = 1.739 Fail to reject HO. df= 17 t critical value to 05 = 1.782 Fail to reject HO. df= 17 t critical value to.025 = 1.986 Fail to reject HO. df= 17 t critical value to.025 = 1.986 Reject H0. df= 17 t critical value to.05 = 1.739 Reject HO.
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