An equilibrium mixture contains 0.350 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the reactants (carbon monoxide and water vapor) in a 1.00 L container. CO(g) + H₂O(g) ⇒ CO₂(g) + H₂(g) How many moles of carbon dioxide would have to be added at constant temperature and volume to increase the amount of carbon monoxide to 0.300 mol once equilibrium has been reestablished? moles of CO₂: mol

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ChapterU6: Showtime: Reversible Reactions And Chemical Equilibrium
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An equilibrium mixture contains 0.350 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of
the reactants (carbon monoxide and water vapor) in a 1.00 L container.
CO(g) + H₂O(g) ⇒ CO₂(g) + H₂(g)
How many moles of carbon dioxide would have to be added at constant temperature and volume to increase the amount of
carbon monoxide to 0.300 mol once equilibrium has been reestablished?
moles of CO₂:
mol
Transcribed Image Text:An equilibrium mixture contains 0.350 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the reactants (carbon monoxide and water vapor) in a 1.00 L container. CO(g) + H₂O(g) ⇒ CO₂(g) + H₂(g) How many moles of carbon dioxide would have to be added at constant temperature and volume to increase the amount of carbon monoxide to 0.300 mol once equilibrium has been reestablished? moles of CO₂: mol
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