An equilibrium is established according to the following equationHg2 2+(aq) + NO3 −(aq) + 3H+(aq) ⇌ 2Hg2+(aq) + HNO2(aq) + H2 O(l) Kc = 4.6What will happen in a solution that is 0.20 M each in Hg2 2+, NO3 −, H+, Hg2+, and HNO2?(a) Hg2 2+ will be oxidized and NO3 − reduced.(b) Hg2 2+ will be reduced and NO3 − oxidized.(c) Hg2+ will be oxidized and HNO2 reduced.(d) Hg2+ will be reduced and HNO2 oxidized.(e) There will be no change because all reactants and products have an activity of 1.
An equilibrium is established according to the following equationHg2 2+(aq) + NO3 −(aq) + 3H+(aq) ⇌ 2Hg2+(aq) + HNO2(aq) + H2 O(l) Kc = 4.6What will happen in a solution that is 0.20 M each in Hg2 2+, NO3 −, H+, Hg2+, and HNO2?(a) Hg2 2+ will be oxidized and NO3 − reduced.(b) Hg2 2+ will be reduced and NO3 − oxidized.(c) Hg2+ will be oxidized and HNO2 reduced.(d) Hg2+ will be reduced and HNO2 oxidized.(e) There will be no change because all reactants and products have an activity of 1.
General Chemistry - Standalone book (MindTap Course List)
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Chapter16: Acid-base Equilibria
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Problem 16.111QP: Ionization of the first proton from H2SO4 is complete (H2SO4 is a strong acid); the acid-ionization...
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An equilibrium is established according to the following equation
Hg2 2+(aq) + NO3 −(aq) + 3H+(aq) ⇌ 2Hg2+(aq) + HNO2(aq) + H2 O(l) Kc = 4.6
What will happen in a solution that is 0.20 M each in Hg2 2+, NO3 −, H+, Hg2+, and HNO2?
(a) Hg2 2+ will be oxidized and NO3 − reduced.
(b) Hg2 2+ will be reduced and NO3 − oxidized.
(c) Hg2+ will be oxidized and HNO2 reduced.
(d) Hg2+ will be reduced and HNO2 oxidized.
(e) There will be no change because all reactants and products have an activity of 1.
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