An element X has a tribromide with the empirical formula XBr3 and a trichloride with the empirical formula XC13. The tribromide is converted to the trichloride according to the equation XBr3 + Cl₂ → XCl3 + Br2 If the complete conversion of 1.004 g of XBr3 results in the formation of 0.578 g of XC13, what is the atomic mass of the element X? Atomic mass X = Submit Answer g/mol Retry Entire Group 9 more group attempts remaining

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Chapter5: Stoichiometry
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An element X has a tribromide with the empirical formula XBr3 and a trichloride with the empirical formula XC13. The tribromide
is converted to the trichloride according to the equation
XBr3 + Cl2 → XCl3 + Br₂
If the complete conversion of 1.004 g of XBr3 results in the formation of 0.578 g of XC13, what is the atomic mass of the element
X?
Atomic mass X =
Submit Answer
g/mol
Retry Entire Group 9 more group attempts remaining
Transcribed Image Text:Use the References to access important values if needed for this question. An element X has a tribromide with the empirical formula XBr3 and a trichloride with the empirical formula XC13. The tribromide is converted to the trichloride according to the equation XBr3 + Cl2 → XCl3 + Br₂ If the complete conversion of 1.004 g of XBr3 results in the formation of 0.578 g of XC13, what is the atomic mass of the element X? Atomic mass X = Submit Answer g/mol Retry Entire Group 9 more group attempts remaining
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