An electric circuit, consisting of a capacitor, resistor, and an electromotive force can be modeled by the differential equation R dq/dt +1/C q = E(t), where R and C are constants (resistance and capacitance) and q = q(t) is the amount of charge on the capacitor at time t. For simplicity in the following analysis, let R = C = 1, forming the differential equation dq/dt + q = E(t). In Exercises 17–20, an electromotive force is given in piecewise form, a favorite among engineers. Assume that the initial charge on the capacitor is zero [q(0) = 0]. (i) Use a numerical solver to draw a graph of the charge on the capacitor during the time interval [0, 4]. (ii) Find an explicit solution and use the formula to determine the charge on the capacitor at the end of the four-second time period. E(t)=5 if 0=2

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An electric circuit, consisting of a capacitor, resistor, and
an electromotive force can be modeled by the differential
equation
R dq/dt +1/C q = E(t),
where R and C are constants (resistance and capacitance) and
q = q(t) is the amount of charge on the capacitor at time
t. For simplicity in the following analysis, let R = C = 1,
forming the differential equation dq/dt + q = E(t). In Exercises 17–20, an electromotive force is given in piecewise form,
a favorite among engineers. Assume that the initial charge on
the capacitor is zero [q(0) = 0].
(i) Use a numerical solver to draw a graph of the charge on
the capacitor during the time interval [0, 4].
(ii) Find an explicit solution and use the formula to determine
the charge on the capacitor at the end of the four-second
time period.

E(t)=5 if 0<t<2

E(t)=0 if t>=2

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