Advanced Technologies, Inc. is evaluating two alternatives to produce its new plastic filament with tribological (low friction) properties for creating custom bearing for 3-D printers. The estimates associated with its alternatives are shown below. Use LCM way and a MARR of 20% per year.
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- For the cash flows shown, determine the incremental cash flow between machines B and A for (a) year 0, (b) in year 3, and (c) in year 6. Machine First Cost, $ АОС, $/year Salvage value, $ 3,000 Life, years B -15,000 -25,000 -1,600 -400 6,000 3 4 O (a) = -10000 (b) = -1800 (c) = 1200 %3D !3! O (a) = -10000 (b) = 13200 (c) = 4200 !3! %3! O (a) = -10000 (b) = 13200 (c) =6000 %3! %3D O (a) = -10000 (b) = 13200 (c) = 13200 %3DA large textile company is trying to decide which sludge dewatering process it should use ahead of its sludge drying operation. The costs associated with centrifuge and belt press systems are shown. Compare them on the basis of their annual worths using an interest rate of 10% per year. System First cost, $ Centrifuge -250,000 -31,000 Belt Press -170,000 -35,000 -26,000 10,000 4 AOC, $/year Overhaul in year 2, $ Salvage value, $ Life, years The annual worth of the centrifuge system is $- The system selected on the basis of the annual worth analysis is the (Click to select) ✓ system. 40,000 6 and the annual worth of the belt press system is $-Which alternative in the table below should be selected when the MRR = 6% per year? The life of each Kalternative is 10 years. Increment Considered A Investment cost A (Annual Revenues less. Costs) IRR on A Investment Cost A(A-DN) $800 $154 14.1% The IRR on A(C-B) is %. (Round to one decimal place.) A(B-A) $700 $114 10.0% A(C-B) $1,100 $170 ? A(D-C) $1,300 $130 2
- QUESTION 8 Two processes can be used for producing a polymer that reduces friction loss in engines. Which process should be selected on the basis of a present worth analysis using the LCM, at an interest rate of 10% per year? Answer the below questions to select the best Option. Process A Process B First cost, $ 1,397,151 534,579 Annual operating cost, $ per year 90,383 32,000 Salvage value, $ 80,000 130,000 Update cost at year 2, $ 15,000 Life, years 4 8 EGN 3212 - Eco PW for Process A-You received a memo that you are appointed as the team leader for a new commercial building project. Based on the estimation, if your team will be using a steel, it will cost 80,000 per month and 145000 cost if glass For the plan A, it has an annualmaintenance cost is 25000, 1000 repair cost every 2 years and a salvage value of 3000 after 15 years For the plan B, the repair cost is 3500 every 3 years, annual maintenance cost of 30000 and a salvage value of 1000 after 20 years. Compute for the capitalized cost if the money is worth 8% compounded annually and choose the best material for the project.CC PlanA = (2 decimal placesCC Plan B = (2 decimal places)K Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with tribological (ie, low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 15% per year, which alternative has the lower present worth? Method First Cost M&O Cost, per Year Salvage Value Life DDM $-200,000 $-40,000 $2,000 2 years The present worth for the DDM method is $2635271 The present worth for the LS method is $ The [(Click to select) method is selected LS $-500,000 $-40,000 $21,000 4 years
- Check my work Two processes can be used for producing a polymer that reduces friction loss in engines. Process T will have a first cost of $740,000, an operating cost of $98.000 per year, and a salvage value of $80,000 after its 2-year life. Process W will have a first cost of $1,180,000, an operating cost of $25,000 per year, and a $120,000 salvage value after its 4-year life. Process W will also require updating at the end of year 2 at a cost of $90,000. Which process should be selected on the basis of a present worth analysis at a MARR of 12% per year? The present worth of process T is $- The process selected on the basis of the present worth analysis is process W and the present worth of process W is $-"There are three machines in the mechancical engineering lab A. B, and C and need to be evaluated economically. Machine A has a first cost of $4500, an annual operating cost (AOC) of $900, a salvage value of $200, and a service life 4 years. Machine B has a first cost of $3500, an annual operating cost (AOC) of $700, a salvage value of $350 and a service life 4 years. Machine C has a first cost of $6000, an annual operating cost (AOC) of $50, a salvage value of $100, and a service life 8 years. What is the present worth for machine C? The MARR is 10% per year" -$6,250 -$6,222 -$7,002 -$6,300 O O O OMachine Initial cost, $ Annual cost, $/year Salvage value, $ Life, years O-$87,840 O-$103,910 The estimates for the machines are for two mutually exclusive alternatives. The co of money is 10% per year. The present worth of Machine X is closest to: O $114,310 $65.270 O X -66,000 -10,000 10,000 At 6 Y -46,000 -15,000 24,000 3
- Required information A company that manufactures magnetic flow meters expects to undertake a project that will have the cash flows estimated. First cost, $ Equipment replacement cost in year 2, $ Annual operating cost, $/year Salvage value, $ Life, years -800,000 -300,000 -850,000 250,000 4 At an interest rate of 10% per year, what is the equivalent annual cost of the project? Find the AW value using tabulated factors. The equivalent annual cost of the project is $-[Required information The TT Racing and Performance Motor Corporation wish to evaluate two alternative machines for NASCAR motor tune- ups. Machine First cost, $ Annual operating cost, $ per year Life, years Salvage value, $ R -250,000 -40,000 3 20,000 Use the AW method at 9% per year to select the better alternative. The annual worth of machine R is $- The better alternative is (Click to select) S -370,500 -50,000 5 20,000 and the annual worth of machine S is $-The fixed cost at Sonny Motors is $5765764 annually. The main product has revenue of $84 per unit and #43 variable cost. Then the annual profit if 285163 units are sold is