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Add the mechanism arrows to the reactions below to show the breaking and formation of the bonds. Note you could also express your mechanism arrows as numbers! HO: + CH3 CH3-C-CH3 - 11 X2 As numbers? HO: H3C CH3 H CH3-CC-H- Cl2 Н 71 + H3C H3C then -CH3 -- CH3 H 4 H3 нза ®са —C -н н 5 1-3LA Н As numbers? then CH3-C CB-H 53 16 H2 но-мо 3:0-H Н then CH3 H3C H3C 50 + Ca - Bre H3C H3C Н CH3 CH3-C-OH CH3 н As numbers, this mechanism would be '1234' CH3 + -о-н I CH3 H4 CH3-C Н Н је + + CI + + НО-Н As numbers? + н-о-н Н :о-н Н € н-о-н Н

Add the mechanism arrows to the reactions below to show the breaking and formation of the bonds. Note you could also express your mechanism arrows as numbers! HO: + CH3 CH3-C-CH3 - 11 X2 As numbers? HO: H3C CH3 H CH3-CC-H- Cl2 Н 71 + H3C H3C then -CH3 -- CH3 H 4 H3 нза ®са —C -н н 5 1-3LA Н As numbers? then CH3-C CB-H 53 16 H2 но-мо 3:0-H Н then CH3 H3C H3C 50 + Ca - Bre H3C H3C Н CH3 CH3-C-OH CH3 н As numbers, this mechanism would be '1234' CH3 + -о-н I CH3 H4 CH3-C Н Н је + + CI + + НО-Н As numbers? + н-о-н Н :о-н Н € н-о-н Н

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Add the mechanism arrows to the reactions below to show the breaking and formation of the bonds. Note you could also express your mechanism arrows as numbers! HO: CH3 CH3 3-C-CH3 C₂-CH3 f--- H₂C О H3C CH3 H As numbers? ___, then____________, then Cl2 89 но:9 на но-с CH3 H CH3-C-Cв -H 5 3 H2 89 3:0-H H Он then CH3 Bre Se CH3 H3 H СН3-С -С -н -С -н н CIO f-3+S кот H₂C As numbers? CH3 СН3-с-о-н CH3 H4 H3C Н на детски H3C H As numbers, this mechanism would be '1234' CH3 C-OH CH3 Са + јӘ + + НО-Н I—O:% + н-о-н H As numbers? :O-H н-о-н
Transcribed Image Text:Add the mechanism arrows to the reactions below to show the breaking and formation of the bonds. Note you could also express your mechanism arrows as numbers! HO: CH3 CH3 3-C-CH3 C₂-CH3 f--- H₂C О H3C CH3 H As numbers? ___, then____________, then Cl2 89 но:9 на но-с CH3 H CH3-C-Cв -H 5 3 H2 89 3:0-H H Он then CH3 Bre Se CH3 H3 H СН3-С -С -н -С -н н CIO f-3+S кот H₂C As numbers? CH3 СН3-с-о-н CH3 H4 H3C Н на детски H3C H As numbers, this mechanism would be '1234' CH3 C-OH CH3 Са + јӘ + + НО-Н I—O:% + н-о-н H As numbers? :O-H н-о-н
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