Add curved arrow(s) to draw step 2 of the mechanism. Modify the given drawing of the product as needed to show the intermediate that is formed in this step. Use the +/- tools to add/remove charges, and use the single bond tool to interconvert between double and single bonds. / + :Ö 1 H C N о P S F CI Br
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- 027 In Part 1 add the curved arrows to the nucleophilic acyl substitution reaction mechanism. In Part 2, answer the multiple-choice question about the reaction in Part 1. Part 1 4 See Periodic Table O See Hint :0: :Br: Add the missing curved arrow notation. S CI Br Part 2 Which statement is most correct regarding the equilibrium for the above reaction? Choose one: O The equilibrium favors the right (i.e., Kea > 1) because acetate is a better leaving group than bromide. O The equilibrium favors the right (i.e., Kea > 1) because bromide is a better leaving group than acetate. O The equilibrium favors the left (i.e., Keq« 1) because acetate is a better leaving group than bromide. O The equilibrium favors the left (i.e., Keg 1) because bromide is a better leaving group than acetate. +Add any remaining curved arrow(s) to draw step 1 of one of the mechanisms. Modify the given drawing of the product as needed to show the intermediate that is formed in this step. Use the +/- tools to add/remove charges, and use the single bond tool to interconvert between double and single bonds. CH3 CH3 H;C, H,C CH3 CH3 ČH3 ČH3 + Edit DrawingWhat is the Potential energy diagram for this reaction. Pls draw with as much detail as possible. labels and scale) 2-methylpropan-2-ol ---> 2-methylpropene +H2O Draw the potential energy diagram for the reaction of 2-methylpropan-2-ol ---> 2-methylpropene + H20 (1) Label the structures of the (a) reactants, (b) intermediates, (c) transition states, (d) products, and (e) activation energies (E.) for each step. (2) Which step is the rate-determining step? (3) Identify the electrophile and nucleophile in each step when applicable.
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. + :6: Select to Add Arrows ci :Cl: O AI :CI:Mechanism. Provide the complete mechanism for the reaction below. You must include appropriate arrows, intermediates, and formal charges. OH HO, H2SO4 (cat.) reflux7) Assign partial charges on the Cl-Cl (polarized) below. This reaction proceeds through a three-membered ring halonium intermediate. The first step involves arrows similar to the carbene reaction above plus an additional arrow showing the Cl-Cl bond breaking. The second step is SN2 at the more substituted carbon. 8) Complete the following reaction by adding curved arrows, intermediates, and the expected products. St r :CI-CI: :CI: 9) Label the Mechanistic steps above and the halonium ion intermediate. Because the second step is similar to SN2 the halides add anti to each other.
- ow the mechanism for the following reaction conducted at -5 °C in CC14: cyclohexene + bromine yields a dibromocyclohexane Draw structures - including charges and electrons - and add curved arrows. Details count. Step 1 Add three curved arrows to the first step. Draw the step 1 products: 1 organic species; 1 inorganic species. Step 2 • Reproduce the step 1 products. Add two curved arrows to show the bromide ion reacting with the organic species. Draw the final product. 1L o ↑ MapIn Part 1 add the curved arrows to the nucleophilic acyl substitution reaction mechanism. In Part 2, answer the multiple-choice question about the reaction in Part 1. Part 1 See Periodic Table O See Hint :ö: :Br: Add the missing curved arrow notation. 20 F CI Br I Part 2 Which statement is most correct regarding the equilibrium for the above reaction? Choose one: O The equilibrium favors the right (i.e., Kea > 1) because acetate is a better leaving group than bromide. O The equilibrium favors the right (i.e., Keg > 1) because bromide is a better leaving group than acetate. O The equilibrium favors the left (i.e. Keg « 1) because acetate is a better leaving group than bromide. O The equilibrium favors the left (i.e., Keg« 1) because bromide is a better leaving group than acetate.5.) Please draw the products for the following reaction and draw the mechanism. HBr excess
- The reactants, intermediates, final products, and all curved arrows showing bonds forming andbreaking are collectively referred to as the mechanism of a reaction. For the following reactants: a. Explain why the original statement of Markovnikov’s rule does not help in this case, but themodern restatement of Markovnikov’s rule tells you which carbon will get the X (Cl). b. Show the mechanism of the most likely addition reaction between the reactants.Add curved arrow(s) to draw step 1 of the mechanism. Modify the given drawing of the product as needed to show the intermediate that is formed in this step. Use the +/-tools to add/remove charges, and use the single bond tool to interconvert between double and single bonds. CH3 0. H + :Ö=CH3 Edit Drawing CH3 NH SUPPORTCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. Drawing Arrows N Jo Br: Na Ⓒ Q *N. Na+