Any 1 of the following questions a. Give a reason on why Ka1 for dicarboxylic acid A is only 9 times larger than its K₁:2value whereas K₁1 for dicarboxylic acid B is 724 times larger than its K₁2 value. (4%)OHOOHHOOHpka:1 = 4.55 Ka:1/Ka:2 = 9pK2= 5.50pk1 = 2.83pK2= 5.69Ka:1/Ka:2 = 724b. When a HI(aq) solution is titrated with a strong base at 25 °C the equivalence pointoccurs at pH 7 whereas the equivalence point occurs above pH 7 when a CH3CO₂H(aq)solution is titrated with a strong base at the same temperature. Explain why theequivalence point occurs at different pH values in the two titrations (6%).c. Arrange the monoprotic acids C3H6O2, C2H6O2, CHNO4, and CH₂O2 after increasingacidity from left to right by using the following data (II= osmotic pressure) (5%):II=251 kPa for a 0.100 M C3H6O2(aq) solution at 25 °C•II-254 kPa for a 0.100 M C7H6O₂(aq) solution at 25 °C• II=263 kPa for a 0.100 M CHNO4(aq) solution at 25 °C.II=258 kPa for a 0.100 M CH₂O2(aq) solution at 25 °CB

Here, I'm solving question (a). Inductive effect is distance dependent effect, which decreases with…

a. Give a reason on why Ka1 for dicarboxylic acid A is only 9 times larger than its Ka 2 value whereas Ka1 for dicarboxylic acid B is 724 times larger than its K₁2 value. (4%) HO OH HO OH B PK1 = 4.55 pK2 = 5.50 Ka:1/Ka:2 =9 pK:1 = 2.83 pK2 = 5.69 Ka:1/K2 = 724

a. Give a reason on why Ka1 for dicarboxylic acid A is only 9 times larger than its Ka 2 value whereas Ka1 for dicarboxylic acid B is 724 times larger than its K₁2 value. (4%) HO OH HO OH B PK1 = 4.55 pK2 = 5.50 Ka:1/Ka:2 =9 pK:1 = 2.83 pK2 = 5.69 Ka:1/K2 = 724

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter20: Carboxylic Acids And Nitriles

Section20.4: Substituent Effects On Acidity

Problem 7P: Dicarboxylic acids have two dissociation constants, one for the initial dissociation into a...

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Mass Spectrometry

This process is an instrumental method in which a sample is changed to fast moving positive ions by electron bombardment. The charged particles vary due to their different mass to charge ratio and are estimated with the help of this difference. It is also called mass spectroscopy.

Question

Any 1 of the following questions

a. Give a reason on why Ka1 for dicarboxylic acid A is only 9 times larger than its K₁:2
value whereas K₁1 for dicarboxylic acid B is 724 times larger than its K₁2 value. (4%)
O
HO
OH
HO
OH
pka:1 = 4.55 Ka:1/Ka:2 = 9
pK2= 5.50
pk1 = 2.83
pK2= 5.69
Ka:1/Ka:2 = 724
b. When a HI(aq) solution is titrated with a strong base at 25 °C the equivalence point
occurs at pH 7 whereas the equivalence point occurs above pH 7 when a CH3CO₂H(aq)
solution is titrated with a strong base at the same temperature. Explain why the
equivalence point occurs at different pH values in the two titrations (6%).
c. Arrange the monoprotic acids C3H6O2, C2H6O2, CHNO4, and CH₂O2 after increasing
acidity from left to right by using the following data (II= osmotic pressure) (5%):
II=251 kPa for a 0.100 M C3H6O2(aq) solution at 25 °C
•
II-254 kPa for a 0.100 M C7H6O₂(aq) solution at 25 °C
• II=263 kPa for a 0.100 M CHNO4(aq) solution at 25 °C
.
II=258 kPa for a 0.100 M CH₂O2(aq) solution at 25 °C
B

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