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A. Calculate the pH of 35.00 mL of acetic acid using the concentration assigned in Beyond Labz: HC,H;O, (aa) 2H* (aa) +C,H;O; (aa) I Initial Concentration (M) 0.1031 Change in Concentration (M) -x +x +x Equilibrium Concentration (M) 0.1031 - x E Equilibrium Concentration, Calculated (M) 1. Initial concentration [HC,H;O,]o = 0.1031 M 2. K, symbolic expression: [H* ][ C,H;O; ] [HC,H;O3] (x)(x) 3. K, numerical equation with x: 1.8x 105 = 0.1031 -x 4. Quadratic Formula Method a. Quadratic equation: b.Quadratic formula:| 5. Assumption (5% rule) Method a.Equation for x: b.% ionization = 6. Equilibrium concentrations a [HC,H;Ola = b.[H*la = c.[C,H;O; ha = 7. pH =

A. Calculate the pH of 35.00 mL of acetic acid using the concentration assigned in Beyond Labz: HC,H;O, (aa) 2H* (aa) +C,H;O; (aa) I Initial Concentration (M) 0.1031 Change in Concentration (M) -x +x +x Equilibrium Concentration (M) 0.1031 - x E Equilibrium Concentration, Calculated (M) 1. Initial concentration [HC,H;O,]o = 0.1031 M 2. K, symbolic expression: [H* ][ C,H;O; ] [HC,H;O3] (x)(x) 3. K, numerical equation with x: 1.8x 105 = 0.1031 -x 4. Quadratic Formula Method a. Quadratic equation: b.Quadratic formula:| 5. Assumption (5% rule) Method a.Equation for x: b.% ionization = 6. Equilibrium concentrations a [HC,H;Ola = b.[H*la = c.[C,H;O; ha = 7. pH =

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter16: Principles Of Chemical Reactivity: The Chemistry Of Acids And Bases
Section: Chapter Questions
Problem 127SCQ
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A. Calculate the pH of 35.00 mL of acetic acid using the concentration assigned in Beyond Labz: HC,H;O, (aa) 2H* (aa) +C,H;O; (aa) I Initial Concentration (M) 0.1031 Change in Concentration (M) -x +x +x Equilibrium Concentration (M) 0.1031 - x E Equilibrium Concentration, Calculated (M) 1. Initial concentration [HC,H;O,]o = 0.1031 M 2. K, symbolic expression: [H* ][ C,H;O; ] [HC,H;O3] (x)(x) 3. K, numerical equation with x: 1.8x 105 = 0.1031 -x 4. Quadratic Formula Method a. Quadratic equation: b.Quadratic formula:| 5. Assumption (5% rule) Method a.Equation for x: b.% ionization = 6. Equilibrium concentrations a [HC,H;Ola = b.[H*la = c.[C,H;O; ha = 7. pH =
Transcribed Image Text:A. Calculate the pH of 35.00 mL of acetic acid using the concentration assigned in Beyond Labz: HC,H;O, (aa) 2H* (aa) +C,H;O; (aa) I Initial Concentration (M) 0.1031 Change in Concentration (M) -x +x +x Equilibrium Concentration (M) 0.1031 - x E Equilibrium Concentration, Calculated (M) 1. Initial concentration [HC,H;O,]o = 0.1031 M 2. K, symbolic expression: [H* ][ C,H;O; ] [HC,H;O3] (x)(x) 3. K, numerical equation with x: 1.8x 105 = 0.1031 -x 4. Quadratic Formula Method a. Quadratic equation: b.Quadratic formula:| 5. Assumption (5% rule) Method a.Equation for x: b.% ionization = 6. Equilibrium concentrations a [HC,H;Ola = b.[H*la = c.[C,H;O; ha = 7. pH =
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