pls. see the attached photo, please help me huhu A. By default, the positions are on x1 = - 1.00m and x2 = +1.00m. Adjust the elasticity to 100%.Then set the values of mass and velocity based on the given on the table below. Complete thetable by writing the values for the final velocities and final momentum.FinalVelocitiesMassInitialInitialTotalFinalTotal(kg)VelocitiesMomentumInitialMomentumFinalTrials(m/s)(kg-m/s)Momentum(m/s)(kg m/s)Momentum(kg m/s)(kg m/s)mi= 0.50Vi= 1.25pi=Vi =pi =Trial 1p=p=m= 1.00V2= -1.00p2=V2 =P2 =Vi =vz=pi =p2 =mi= 1.35Vi= 0.80pi=Trial 2p=p=m2= 0.90V2= -1.60p2= By default, the positions are on x1 = - 1.00m and x2=+1.00m.. Adjust the elasticity to 0%. Thenset the values of mass and velocity based on the given on the table below. Complete the table bywriting the values for the final velocities and final momentum.MassInitialInitialTotalFinalFinalTotalTrials(kg)VelocitiesMomentumInitialVelocitiesMomentumFinal(m/s)(kg m/s)Momentum(m/s)(kg-m/s)Momentum(kg-m/s)(kg-m/s)Trial 1mi= 0.50Vi= 1.25pi=Vị =Pi =m2= 1.00V2= -1.00p=p=p2=V2p2 =mi= 1.35Vi= 0.80VI =V2 =Pi=Pi =p2 =Trial 2m2= 0.90V2= -1.60p=p3=p2=

As given that Position 1 is X1 =-1.0 m and position 2 is X2=1.0 m . From this, we assume that the…

A. By default, the positions are on x1 1.00m and x2 +1.00m. Adjust the elasticity to 100%. Then set the values of mass and velocity based on the given on the table below. Complete the table by writing the values for the final velocities and final momentum. Mass (kg) Initial Velocities Momentum (kg m/s) Initial Total Initial Final Velocities Momentum (m/s) Final Total Final Trials (m/s) Momentum (kg-m/s) Momentum (kg-m/s) (kg m/s) Trial 1 mi= 0.50 Vi= 1.25 pi= vi= pi p= p= my= 1.00 V= -1.00 V2= p2 mi= 1.35 Vi= 0.80 pi= Vi= Trial 2 p= p= m2= 0.90 V2= -1.60 V2= p2 =

A. By default, the positions are on x1 1.00m and x2 +1.00m. Adjust the elasticity to 100%. Then set the values of mass and velocity based on the given on the table below. Complete the table by writing the values for the final velocities and final momentum. Mass (kg) Initial Velocities Momentum (kg m/s) Initial Total Initial Final Velocities Momentum (m/s) Final Total Final Trials (m/s) Momentum (kg-m/s) Momentum (kg-m/s) (kg m/s) Trial 1 mi= 0.50 Vi= 1.25 pi= vi= pi p= p= my= 1.00 V= -1.00 V2= p2 mi= 1.35 Vi= 0.80 pi= Vi= Trial 2 p= p= m2= 0.90 V2= -1.60 V2= p2 =

Principles of Heat Transfer (Activate Learning with these NEW titles from Engineering!)

8th Edition

ISBN:9781305387102

Author:Kreith, Frank; Manglik, Raj M.

Publisher:Kreith, Frank; Manglik, Raj M.

Chapter5: Analysis Of Convection Heat Transfer

Section: Chapter Questions

Problem 5.5P: Evaluate the dimensionless groups hcD/k,UD/, and cp/k for water, n-butyl alcohol, mercury, hydrogen,...

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