A well-known brokerage firm executive claimed that 60% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 200 people, 58% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is smaller than 60% at the 0.005 significance level. The null and alternative hypothesis would be: Ho:µ = 0.6 Ho: p < 0.6 Ho:µ > 0.6 Họ:µ < 0.6 Ho:p = 0.6 Ho:p> 0.6 H1 : µ # 0.6 H1:p > 0.6 H1:µ < 0.6 H1:µ > 0.6 H1:p# 0.6 H1:p< 0.6 The test is: left-tailed right-tailed two-tailed The test statistic is: |(to 3 decimals) The p-value is: |(to 4 decimals)

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter13: Probability And Calculus
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A well-known brokerage firm executive claimed that 60% of investors are currently confident of meeting
their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in
a sample of 200 people, 58% of them said they are confident of meeting their goals.
Test the claim that the proportion of people who are confident is smaller than 60% at the 0.005
significance level.
The null and alternative hypothesis would be:
Но: и — 0.6 Но:р < 0.6 Но:д 2 0.6 Но:д < 0.6 Но:р — 0.6 Но:р > 0.6
Hi:и 2 0.6 Hі:p> 0.6 Нj:р < 0.6 Hi:д > 0.6 Hi:р#0.6 Hi:р< 0.6
The test is:
left-tailed right-tailed two-tailed
The test statistic is:
(to 3 decimals)
The p-value is:
|(to 4 decimals)
Transcribed Image Text:A well-known brokerage firm executive claimed that 60% of investors are currently confident of meeting their investment goals. An XYZ Investor Optimism Survey, conducted over a two week period, found that in a sample of 200 people, 58% of them said they are confident of meeting their goals. Test the claim that the proportion of people who are confident is smaller than 60% at the 0.005 significance level. The null and alternative hypothesis would be: Но: и — 0.6 Но:р < 0.6 Но:д 2 0.6 Но:д < 0.6 Но:р — 0.6 Но:р > 0.6 Hi:и 2 0.6 Hі:p> 0.6 Нj:р < 0.6 Hi:д > 0.6 Hi:р#0.6 Hi:р< 0.6 The test is: left-tailed right-tailed two-tailed The test statistic is: (to 3 decimals) The p-value is: |(to 4 decimals)
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