(a) Weight of empty crucible 16-440 (b) Weight of crucible + magnesium 16-75215 (c) Weight of magnesium in crucible 0-312 9 (d) Weight of crucible after heating 16-954 9 0.517 9 И90 0.312 g Mg x I mol MaD. x (e) Weight of magnesium oxide present , ты ма 40.3049 mgo ·x 24-305 ама Imol Mg Imal Mgo absorbed by magnesium 0-5 mỗi bê ма ма (f) Weight of oxygen I mol Mg 0.2059 X X 1 -X.32 9 0₂- 1 mol 0₂ = 0·20590 Mg 24-305g (g) Moles of magnesium used 0.01284 0312 g Mg x 1 molimg. 24-305 = 0.01284 mol Mg gMg (h) Moles of oxygen 0-01284 Imol 0-312 9 mg x (i) Ratio of magnesium/oxygen Ratio Mg=0= (j) % error in experiment 16.7529-16.4409=0-312 9 0-312g Mg absorbed I mol Mg 24-3059 Mg mol Ma Mol 0 у Imol (1 mol 9 -0.517 g MgO mol Mg = 0·01284 mol Mg 3-417 0-9651 mol) /0.96516 mol xivo)=3-617-
(a) Weight of empty crucible 16-440 (b) Weight of crucible + magnesium 16-75215 (c) Weight of magnesium in crucible 0-312 9 (d) Weight of crucible after heating 16-954 9 0.517 9 И90 0.312 g Mg x I mol MaD. x (e) Weight of magnesium oxide present , ты ма 40.3049 mgo ·x 24-305 ама Imol Mg Imal Mgo absorbed by magnesium 0-5 mỗi bê ма ма (f) Weight of oxygen I mol Mg 0.2059 X X 1 -X.32 9 0₂- 1 mol 0₂ = 0·20590 Mg 24-305g (g) Moles of magnesium used 0.01284 0312 g Mg x 1 molimg. 24-305 = 0.01284 mol Mg gMg (h) Moles of oxygen 0-01284 Imol 0-312 9 mg x (i) Ratio of magnesium/oxygen Ratio Mg=0= (j) % error in experiment 16.7529-16.4409=0-312 9 0-312g Mg absorbed I mol Mg 24-3059 Mg mol Ma Mol 0 у Imol (1 mol 9 -0.517 g MgO mol Mg = 0·01284 mol Mg 3-417 0-9651 mol) /0.96516 mol xivo)=3-617-
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter2: Atoms Molecules And Ions
Section: Chapter Questions
Problem 165SCQ
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i) What is the ratio of Magnesium/oxygen
j) What is the percent error in the experiment?
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