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A voltaic cell is composed of the following 2 half reactions: Mn²+ (aq) + 2e → › Mn(s) Ecell = -1.185 V Cu+ (aq) + e Cu(s) Eell = 0.521 V Determine the non-standard state Ecell at 298 K when Mn²+ (aq) = 0.158 M and Cu+ (aq) = 0.663 M. → V

A voltaic cell is composed of the following 2 half reactions: Mn²+ (aq) + 2e → › Mn(s) Ecell = -1.185 V Cu+ (aq) + e Cu(s) Eell = 0.521 V Determine the non-standard state Ecell at 298 K when Mn²+ (aq) = 0.158 M and Cu+ (aq) = 0.663 M. → V

Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter19: Principles Of Chemical Reactivity: Electron Transfer Reactions
Section19.4: Standard Electrochemical Potentials
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A voltaic cell is composed of the following 2 half reactions: Mn²+ (aq) + 2e → > Mn(s) Ecell = -1.185 V Cu+ (aq) + e Cu(s) Eell = 0.521 V Determine the non-standard state Ecell at 298 K when Mn²+ (aq) = 0.158 M and Cu+ (aq) = 0.663 M. → V
Transcribed Image Text:A voltaic cell is composed of the following 2 half reactions: Mn²+ (aq) + 2e → > Mn(s) Ecell = -1.185 V Cu+ (aq) + e Cu(s) Eell = 0.521 V Determine the non-standard state Ecell at 298 K when Mn²+ (aq) = 0.158 M and Cu+ (aq) = 0.663 M. → V
Score on last try: 0 of 2 pts. See Details for more. You can retry this question below Determine the equilibrium constant, K, for the voltaic cell composed of the following 2 half reactions at 298 K. 2+ Sn²+ (aq) + +2e → Sn(s) Ecell = -0.136 V Mn2+ ²+ (aq) + 2e¯¯→ Mn(s) Ell-1.19 V Report your answer in the format 2.4E-3. 1.87E-36 Hint: Decide which half-reaction is the reduction reaction and which one is the oxidation reaction by looking at Eº; the oxidation reaction should be reversed, and will have the opposite sign. 4.0560949048976E+35
Transcribed Image Text:Score on last try: 0 of 2 pts. See Details for more. You can retry this question below Determine the equilibrium constant, K, for the voltaic cell composed of the following 2 half reactions at 298 K. 2+ Sn²+ (aq) + +2e → Sn(s) Ecell = -0.136 V Mn2+ ²+ (aq) + 2e¯¯→ Mn(s) Ell-1.19 V Report your answer in the format 2.4E-3. 1.87E-36 Hint: Decide which half-reaction is the reduction reaction and which one is the oxidation reaction by looking at Eº; the oxidation reaction should be reversed, and will have the opposite sign. 4.0560949048976E+35
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