A variables sampling plan (VSP) for defectives is required for a process with two-sided spec limits USL/LSL = 75±5. The VSP must meet the following conditions ■ Accept 95% of 0.5% defective lots (Hint: What are the AQL and alpha values?) ■Reject 90% of 2% defective lots (Hint: What are the RQL and beta values?) a. Design the VSP assuming that the population standard deviation is known. (Assume σ = 1) b. Design the VSP assuming that the population standard deviation is unknown. c. Should you accept or reject a lot in the σ unknown case if the sample delivers x = 72.0 and s = 1.5? (You don't have the sample data to use the MINITAB menu. You will have to do the calculation by hand.)
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- 2. Find the quartiles for these data values: 5, 7, 7, 8, 10, 11, 12, 15, 17 OAQ₁ 7.Q₂ Q2 OB. Q₁ 7.Q₂ = 10.Q3 - 13.5 = Oc. Q₁ = 6, Q2 = 9, Q3 = 12 OD. Q₁ 7.5. Q₂ [Am] ( = 11. Q3 = 15 10.5 Q3 = 13.5esc . 1 TextEdit File Edit Times New Roman Bold ! 7 Format View Window Help Hypothesis Test Assignment (1).rtf KHIDEEOD CE 4. The fuel economy sticker on a new SUV's window sticker indicates the owner can expect 16 mpg in city driving and 20 mpg highway driving and 18 mpg overall. Accurate gasoline records for one such vehicle were kept, and a random sample of mileage per tank of gasoline was collected: I. 17.6 17.7 18.1 22.0 17.0 19.4 18.9 17.4 21.0 19.2 18.3 19.1 20.7 16.7 19.4 18.2 18.4 17.1 17.4 15.8 17.9 18.0 16.3 17.5 17.3 20.4 19.1 21.0 18.1 19.0 19.6 18.9 16.8 18.2 17.6 19.1 18.0 16.8 20.9 17.9 17.7 20.3 18.6 19.0 16.5 19.4 18.6 18.6 17.3 18.7 Test whether the population average mpg is actually greater than 18 mpg using a 1% level of significance. a) State the null and alternate hypotheses. b) Would you perform a one-tailed or two-tailed test? Why? c) State the test statistic and p-value of your test. Round your values to four-decimal places. Aw NE 28 PC MacBook Air 8: *FZ 44 Q…Mrs. Paul wants to test that claim that, on average, her students average mark is 85. She pulls therecords of 100 of per past students over a three-year period. The grades inputted into MINITABfor analysis. Exhibit 1 below shows the results of an analysis carried out on the data obtained. Exhibit 1 One-Sample Z: Level I/IITest of mu = 85 vs mu not = 85The assumed sigma = 15.0 Variable N Mean StDev SEMean Z PStudents Score 100 75.4 12.99 * ** *** i. Calculate the SEMean ii. Construct a 98% confidence interval for the population scores of Mrs. Paul’s students.iii. State the null and alternate hypothesis for this test. iv. Calculate the missing value ** and use tables to approximate the value of ***.v. Using a 1% level of significance, state the decision criteria for this test…
- Mrs. Paul wants to test that claim that, on average, her students average mark is 85. She pulls therecords of 100 of per past students over a three-year period. The grades inputted into MINITABfor analysis. Exhibit 1 below shows the results of an analysis carried out on the data obtained.Exhibit 1One-Sample Z: Level I/IITest of mu = 85 vs mu not = 85The assumed sigma = 15.0 Variable N Mean StDev SE Mean Z PStudents Score 100 75.4 12.99 * ** *iv. Calculate the missing value ** and use tables to approximate the value of ***.v. Using a 1% level of significance, state the decision criteria for this test vi. State the conclusion for the test and whyMrs. Paul wants to test that claim that, on average, her students average mark is 85. She pulls therecords of 100 of per past students over a three-year period. The grades inputted into MINITABfor analysis. Exhibit 1 below shows the results of an analysis carried out on the data obtained.Exhibit 1One-Sample Z: Level I/IITest of mu = 85 vs mu not = 85The assumed sigma = 15.0 Variable N Mean StDev SE Mean Z P Students Score 100 75.4 12.99 * ** ***i. Calculate the SEMeanii. Construct a 98% confidence interval for the population scores of Mrs. Paul’s students.iii. State the null and alternate hypothesis for this test.iv. Calculate the missing value ** and use tables to approximate the value of ***v. Using a 1% level of significance, state the decision criteria for this test vi. State the conclusion for the test and whyUnfortunately, arsenic occurs naturally in some ground water. A mean arsenic level of μ=8 parts per billion (ppb) is considered safe for agricultural use. A well in Los Banos is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 37 tests gave a sample mean of x=7.3 ppb arsenic. It is known that σ=1.9 ppb for this type of data. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use the classical approach. Use α=0.01 What is the hypotheses for this problem? A: Ho μ =7.3ppb vs HA μ < 7.3ppb B: Ho μ <7.3ppb vs HA μ ≥ 7.3ppb C: Ho μ =8.0ppb vs HA μ < 8.0ppb D: Ho μ <8.0ppb vs HA μ ≥ 8.0ppb
- Unfortunately, arsenic occurs naturally in some ground water. A mean arsenic level of u = 8 parts per billion (ppb) is considered safe for agricultural use. A well in Los Banos is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 37 tests gave a sample mean of = 7.3ppb arsenic. It is known that o = 1.9 ppb for this type of data. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use the classical approach. Use a = 0.01 What is the Decision (step 5) for this problem? There is not sufficient evidence at the 0.01 level of significance to show the mean arsenic level in the Los Banos well is less than 7.3 ppb. O There is sufficient evidence at the 0.01 level of significance to show the mean arsenic level in the Los Banos well is less than 8.0 ppb. There is not sufficient evidence at the 0.01 level of significance to show the mean arsenic level in the Los Banos well is less than 8.0 ppb. O There is…the assumption that the t test for independent samples makes regarding the amount of variability in each of the two groups is called the?Mrs. Paul wants to test that claim that, on average, her students average mark is 85. She pulls the records of 100 of per past students over a three-year period. The grades inputted into MINITAB for analysis. Exhibit 1 below shows the results of an analysis carried out on the data obtained. Exhibit 1 One-Sample z: Level I/II Test of mu = 85 vs mu not = 85 The assumed sigma = 15.0 Variable Mean StDev SE Mean Students Score 100 75.4 12.99 ** +** i. Calculate the SEMean ii. Construct a 98% confidence interval for the population scores of Mrs. Paul's students. State the null and alternate hypothesis for this test. iv. Calculate the missing value ** and use tables to approximate the value of *** Using a 1% level of significance, state the decision criteria for this test State the conclusion for the test and why iii. v. vi.
- You are shown ZJKL below whose measure is 90°. Draw an angle bisector of ZJKL by clicking a dragging a ray out from the vertex at K. Click and drag to draw a ray from the yellow dot. To redraw, click and drag from the yellow dot again. mZJKL = 90° mZJKM = 45° m/LKM = 45° L CMrs. Paul wants to test that claim that, on average, her students average mark is 85. She pulls the records of 100 of per past students over a three-year period. The grades inputted into MINITAB for analysis. Exhibit 1 below shows the results of an analysis carried out on the data obtained. Exhibit 1 One-Sample Z: Level I/II Test of mu = 85 vs mu not = 85 The assumed sigma = 15.0 Variable Mean StDev SE Mean P Students Score 100 75.4 12.99 ** ***A variables sampling plan (VSP) for defectives is required for a process with two-sided spec limits USL/LSL = 75 ±5. The VSP must meet the following conditions ■Accept 95% of 0.5% defective lots (Hint: What are the AQL and alpha values?) ■Reject 90% of 2% defective lots (Hint: What are the RQL and beta values?) a. Design the VSP assuming that the population standard deviation is known. (Assume σ = 1) b. Design the VSP assuming that the population standard deviation is unknown. c. Should you accept or reject a lot in the o unknown case if the sample delivers x = 72.0 and s = 1.5? (You don't have the sample data to use the MINITAB menu. You will have to do the calculation by hand.)