A train on a very long straight level stretch of tracks, starting from a dead stop, steadily speedsup to 28 m/s (about 63 mph) in 14 minutes, and then slows to 18 m/s (about 40 mph) with aconstant deceleration of magnitude 0.011 m/s 2. What was the average speed of the train forthis whole thing (speeding up and slowing down)? Hint: in this problem, if you take the direc-tion the train is going as positive, then average speed is the same thing as average velocity.

Case 1) initial speed = 0 msfinal speed (v) = 28 mstime taken (t) = 14 minutes = 14×60 seconds = 840…

Answered: A train on a very long straight level…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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A train on a very long straight level stretch of tracks, starting from a dead stop, steadily speeds
up to 28 m/s (about 63 mph) in 14 minutes, and then slows to 18 m/s (about 40 mph) with a
constant deceleration of magnitude 0.011 m/s 2. What was the average speed of the train for
this whole thing (speeding up and slowing down)? Hint: in this problem, if you take the direc-
tion the train is going as positive, then average speed is the same thing as average velocity.

Expert Solution

Step 1

$C a s e 1) initial speed = 0 \frac{m}{s} final speed (v) = 28 \frac{m}{s} time taken (t) = 14 m i n u t e s = 14 \times 60 s e c o n d s = 840 s e c o n d s$

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