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A student needs to dilute a 0.23 M Pb(NO3)₂ solution to make 53.0 mL of 0.14 M Pb(NO3)2. Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.23 M Pb(NO3)₂ solution that is needed. 53.0 mL 53.0 L Answer Bank 0.23 M 0.14 M 0.14 mL 0.23 mL = mL

A student needs to dilute a 0.23 M Pb(NO3)₂ solution to make 53.0 mL of 0.14 M Pb(NO3)2. Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.23 M Pb(NO3)₂ solution that is needed. 53.0 mL 53.0 L Answer Bank 0.23 M 0.14 M 0.14 mL 0.23 mL = mL

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 88QRT: You need to make a 0.300-M solution of NiSO4(aq). Calculate the mass of NiSO4 · 6H2O you should put...
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A student needs to dilute a 0.23 M Pb(NO3)₂ solution to make 53.0 mL of 0.14 M Pb(NO3)2. Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.23 M Pb(NO3)2 solution that is needed. 53.0 mL 53.0 L X Answer Bank 0.23 M 0.14 M 0.14 mL 0.23 mL = mL
Transcribed Image Text:A student needs to dilute a 0.23 M Pb(NO3)₂ solution to make 53.0 mL of 0.14 M Pb(NO3)2. Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.23 M Pb(NO3)2 solution that is needed. 53.0 mL 53.0 L X Answer Bank 0.23 M 0.14 M 0.14 mL 0.23 mL = mL
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