A student is carrying out a biological preparation that requires 1M NaCl to maintain an ionic strength of 1.0. The student chooses to use 1.0 M ammonium sulfate instead. Why is this a seri- ous error?
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A: **As you have asked multiple questions, I am solving first question. Either resubmit other questions…
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A: Al2(SO4)3 ----> 2Al3+ + 3SO42- 0.5 M 1 M 1.5 M Ionic strngth = 1/2 ΣCiZi2…
Q: A student is carrying out a biological preparation that requires 1 M NaCl to maintain an ionic…
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Q: The ionic strength of 0.10 M AI(NO3)3 is: O 0.10 O 0.70 O 0.30 O 0.20 O 0.60
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A: The formula used to calculate the ionic strength is as follows,
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Q: The ionic strength of 0.30 M NaCl is: O 0.30 O 0.10 O 0.40 O 0.60 O 0.70
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Q: The ionic strength of 0.10 M AI(NO3)3 is: O 0.30 O 0.10 O 0.70 O 0.60 O 0.20
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Q: The Ka for HF is 7.0 x 10-4 Kb for the fluoride ion is
A: at 25°C Ka x Kb = 10-14 Given that Ka = 7 x 10-4 HF is weak acid and its conjugate base is…
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- (a) Given that Ka for acetic acid is 1.8 x 10-5 and that forhypochlorous acid is 3.0 x 10-8, which is the stronger acid?(b) Which is the stronger base, the acetate ion or the hypochloriteion? (c) Calculate Kb values for CH3COO- and ClO-.Fe3+(aq) + SCN–(aq) ⇆ FeSCN2+(aq) Suppose that the solution of NaSCN was accidentally prepared using too much solid NaSCN, so that that solution had a higher [SCN-] value than expected. How would the resulting measured Keq value differ from the true Keq value: too large, too small, or unaffected? ExplainGiven that Kb for ammonia is 1.8 * 10-5 and that for hydroxylamine is 1.1 * 10-8, which is the stronger base?
- 6. For the ionization of phenylacetic acid, C6H5CH₂CO₂H + H₂O = H3O+ + C6H5CH₂CO₂ K₂ = 49 × 10-5 (a) What is [C6H5CH₂CO₂] in 0.186 M C6H3CH₂CO₂H? (b) What is the pH of 0.121 M C6H3CH₂CO₂H?Write the values of Y and X. H2SO4 CH3CH=CH2 + H2O CH;CH-CH2 H HỌ 2-propanol an alcohol The pKa of a protonated alcohol is about -2.5, and the pKa of an alcohol is about 15. Therefore, as long as the pH of the solution is greater than Y and less than X, more than 50% of 2-propanol will be in its neutral, nonprotonated form. Express your answers using two significant figures separated by a comma. AX中 Y, X = %3|PMB-0OTBS H2 Pd OMe `Ph
- You are viewing Sonjae Wallace's screen REC View Options Q8: Level 3+ (Unit 13, L.G. 11) Given the following information: O1 + H,0 = HOI + OH H,0 = %H;0* + ½OH K, = 5 x 104 K2 = 1 x 107 What is the value of K for the rxn HOI + H,0 = 01+ H,0*? A. 2 x 10-11 B. 5 x 10 11 C. 2x 10-4 D. 4 x 104 To: Type P Type here to search a brt %23 * 4 5 Q Y. LL M alt alt ctri10:11 PM Sun Feb 5 < 5 T B 100% + : 0 DH₂07 2) Na₂Cr₂O₂, H₂SO4, H₂0 7 3). Ph Mg Br 4) +₂0 1 1 < N.Calculate the pH at 25 °C of a 0.13M solution of trimethylammonium chloride ((CH;) NHCI 3 CH;),NHC!) Note that trimethylamine ((CH3),N) i is a weak base with a pK, of 4.19. b. Round your answer to 1 decimal place.
- A 1.0 m solution of HCI in benzene has a freezing point of 0.4 C. Is HCI an electrolyte in benzene? Explain.(Use this to answer Qs 24-29.) Bill Nye the Science Guy is at it again and wants to show the chemistry students how a buffer works. He creates a buffer by mixing 50.0 mL of 0.450 M HF and 50.0 mL of 0.450 MF. Just like the titration experiment, he has no idea how it works. Because of your generous nature, you decide to help him with the following questions. 24) To make a buffer, what needs to be mixed together? a) A weak acid with its conjugate base or a weak base with its conjugate acid b) A strong acid and a strong base c) A strong acid and a weak base d) A strong base and a weak acidThe peptide below is placed into a buffer with a pH = 1.54 OH -NH-CH-C -NH—CH— с—ОН -NH-CH-C H;N-CH- CH2 -NH -CH-C ČH2 CH2 ČH3 CH2 C: :O NH2 CH2 OH H2G NH3 What direction will the peptide move? If it will move towards the positive electrode give your answer as 1 If it will move towards the negative electrode give your answer as -: If it will not move give your answer as 0