A spring with an 8 kg mass is kept stretched 0.4 m beyond its natural length by a force of 32 N. The spring starts at its equilibrium position and is given an initial velocity of 5 m/s. Find the position (in m) of the mass at any time t. x(t) = 1.5811 sin(√10 t) X m

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter6: Vector Spaces
Section6.7: Applications
Problem 18EQ
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A spring with an 8 kg mass is kept stretched 0.4 m beyond its natural length by a force of 32 N. The spring starts at its equilibrium position and is given an initial velocity of 5 m/s. Find the position (in m) of the mass at any time t.
x(t) = _______ m
 
x(t) = 1.5811sin(√10t) m --- this was marked wrong. Please help
A spring with an 8 kg mass is kept stretched 0.4 m beyond its natural length by a force of 32 N. The spring starts at its
equilibrium position and is given an initial velocity of 5 m/s. Find the position (in m) of the mass at any time t.
x(t) = 1.5811 sin(√10 t)
m
Transcribed Image Text:A spring with an 8 kg mass is kept stretched 0.4 m beyond its natural length by a force of 32 N. The spring starts at its equilibrium position and is given an initial velocity of 5 m/s. Find the position (in m) of the mass at any time t. x(t) = 1.5811 sin(√10 t) m
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