A section of commercial steel shafting 2.0 m long between bearings carries a 1000 N pulley at its midpoint, as shown in Figure. The pulley is keyed to the shaft and receives 30 kW at 150 rev/min, which is transmitted to a flexible coupling just outside the right bearing. The belt drive is horizontal and the sum of the belt tensions is 8000 N. Assume k = kh =1.5, og = 55 MPa, G = 80 GPa. Calculate the necessary shaft diameter ?( the left side and the right side should be the same)

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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A section of commercial steel shafting 2.0 m long between bearings carries a 1000 N pulley at its midpoint, as shown in Figure. The pulley is keyed to the shaft
and receives 30 kW at 150 rev/min, which is transmitted to a flexible coupling just outside the right bearing. The belt drive is horizontal and the sum of the belt
tensions is 8000 N. Assume kt = kp =1.5, Os
= 55 MPa, G = 80 GPa. Calculate the necessary shaft diameter ?( the left side and the right side should be the same)
100 cm
100 cm
T2
O 8.5 cm
O 850 cm
O 0.85 cm
Transcribed Image Text:A section of commercial steel shafting 2.0 m long between bearings carries a 1000 N pulley at its midpoint, as shown in Figure. The pulley is keyed to the shaft and receives 30 kW at 150 rev/min, which is transmitted to a flexible coupling just outside the right bearing. The belt drive is horizontal and the sum of the belt tensions is 8000 N. Assume kt = kp =1.5, Os = 55 MPa, G = 80 GPa. Calculate the necessary shaft diameter ?( the left side and the right side should be the same) 100 cm 100 cm T2 O 8.5 cm O 850 cm O 0.85 cm
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