A scientist studying local lakes claims that there is a linear relationship between a lake’s level of mercury and the lake’s depth. The scientist collected data to test the claim at a significance level of α=0.01. The following hypotheses were tested. H0:β1=0Ha:β1≠0 The test yielded a t-value of 2.7 and a p-value of 0.012. Which of the following is a correct conclusion about the scientist’s claim?

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter1: Functions
Section1.2: The Least Square Line
Problem 8E
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A scientist studying local lakes claims that there is a linear relationship between a lake’s level of mercury and the lake’s depth. The scientist collected data to test the claim at a significance level of α=0.01. The following hypotheses were tested.

H0:β1=0Ha:β1≠0

The test yielded a t-value of 2.7 and a p-value of 0.012. Which of the following is a correct conclusion about the scientist’s claim?

 
 
  • The null hypothesis is rejected since 0.012>0.01. There is sufficient evidence to suggest that there is a linear relationship between a lake’s level of mercury and the lake’s depth.

    A
  • The null hypothesis is not rejected since 0.012>0.01. There is sufficient evidence to suggest that there is a linear relationship between a lake’s level of mercury and the lake’s depth.

    B
  • The null hypothesis is rejected since 0.012>0.01. There is not sufficient evidence to suggest that there is a linear relationship between a lake’s level of mercury and the lake’s depth.

    C
  • The null hypothesis is not rejected since 0.012>0.01. There is not sufficient evidence to suggest that there is a linear relationship between a lake’s level of mercury and the lake’s depth.

    D
  • The null hypothesis is accepted since 0.012>0.01. There is sufficient evidence to suggest that there is not a linear relationship between a lake’s level of mercury and the lake’s depth.

    E

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