A process's execution may be preemptively assigned to an I/O queue and then transferred to the CPU when it's ready. There's no telling what may happen if the I/O is suddenly cut off. Is the CPU's burst going to be diminished? How exactly does this hold true?

A process's execution may be preemptively assigned to an I/O queue and then transferred to the CPU when it's ready. There's no telling what may happen if the I/O is suddenly cut off. Is the CPU's burst going to be diminished? How exactly does this hold true?

Name: A process's execution may be preemptively assigned to an I/O queue and
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Description: A process's execution may be preemptively assigned to an I/O queue and then transferred to the CPU when it's ready. There's no telling what may happen if the I/O is suddenly cut off. Is the CPU's burst going to be diminished? How exactly does this ho

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter4: Processor Technology And Architecture

Section: Chapter Questions

Problem 2PE: If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the...

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There are a number of benefits to preemptively assigning processing to an I/O queue and then passing control to the CPU when it's ready. If the I/O is suddenly stopped, who knows what may happen? Will this have an impact on the CPU's burst? How exactly is this the case?
When it comes to process execution, what is the advantage of first allocating it to the I/O queue and then pushing it to the CPU when it is ready? What, in your opinion, will happen if the I/O is not completed correctly? Is the CPU burst going to be affected? What do you mean?
What is the benefit of assigning process execution to the I/O queue first and then pushing it to the CPU when it's ready? What do you think will happen if the I/O is interrupted? Will the CPU burst be affected? How so?
When it is feasible to do so, what are the advantages of moving the execution of the process to the input/output queue first? In the case that the input/output signal is broken, what do you believe will take place? Will this decrease the highest burst rate that the CPU is capable of achieving? What exactly do you mean by saying that? I'm not quite sure I get it.
What's the benefit of assigning a process to the I/O queue before pushing it to the CPU? What will happen if the I/O is wrong? CPU burst? Meaning?
There are a number of benefits that come from the practise of first delegating the execution of a process to an input/output queue and then, once the CPU is ready, handing control back to it. Who knows what may occur if the input/output is suddenly stopped? Will there be an impact on the burst of the central processing unit? How exactly does this hold true?
As a consequence, the CPU suspends all active processes until the interruption is resolved. This is known as interrupting service. Who knows why the present procedure has been stopped? It is not possible to continue with the present operation and then deal with the disruption after it has concluded.
Computer Science A multiprogrammed system with a single CPU has a very large number of CPU boundprocesses running on it that all have the same priority. Could you think of a CPU schedulingalgorithm that would combine the lowest possible response times with the highest possiblethroughput and no starvation
What happens if the priority levels of several processes in cpu scheduling are the same?
Step 1 The CPU needs to suspend the currently executing process when an interrupt has occurred. It prevents the input-output operation from being delayed. Suppose, a user is asked to enter a key while a process is executing and the input of the key is important for the computation. Then the key entered has to be dealt with then and there. That action cannot be suspended. It is also not known how long the current process may take time to execute. So, the operating system gives preference to the interrupt when it occurs. Step 2 If the interrupts are not serviced as soon as they are received, it makes the DMA inefficient. DMA helps in the interaction of I/O devices with the main memory without interacting with the CPU. Therefore, the interrupts have to be serviced as soon as they occur.
You are told that a given system uses Segmentation. The memory is currently full and holds 3 processes "A", "B" and "C" each of size 512KB as well as the kernel whose size is 1024KB. You can assume there is nothing else that is taking up memory. A Timer Interrupt forces a context switch to occur and the scheduler chooses to load process "B" into the CPU and change its state to running. You are told that the base of the stack which grows upwards for processB is found at the very end of our physical memory. You are also told that the last portion of the Address Space for each process is used for the Stack. After the Context switch which process does the values in the segment register correspond to? C + x What is the Physical Address of the base of the stack for ProcessB? (Just give the value in KB) 1536 What is the offset of the Virtual Address 500KB in KB? (Just give the value) 32 What is the Physical Address that the Virtual Address 500KB maps to in KB? (Just give the value) 1524
When feasible, what are the upsides of prioritizing the I/O queue as the place where processes would be executed? If the I/O connection suddenly goes down, what do you expect to happen? How would this affect the fastest possible CPU burst rate? I'm not quite sure I get what you're getting at here.