A population has the following genotype frequencies AA=0.3844, Aa=D0.4712, aa=0.1444. Assuming Hardy-Weinberg equilibrium, what are the allele frequencies in the population?
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- How Can We Measure Allele Frequencies in Populations? What are four assumptions of the HardyWeinberg law?A population of dragons is as follows: 46 are green with genotype GG 106 are green with genotype Gg 56 are red with genotype gg Is this population in Hardy-Weinberg equilibrium? Assume 1 degree of freedom for your chi-square test.The following data were obtained from a Ghanaian population of 152 people. Blood Type Number of Individuals M 61 MN 64 N 27 Calculate the frequencies of the M and N alleles in this population. What are the expected numbers of individuals of each genotypic class in this population? Assume Hardy-Weinberg conditions. Use the chi-squared test to determine if these data fit the Hardy-Weinberg equilibrium model. The degrees of freedom for this test should be 1. Why is this appropriate?
- A hypothetical population of 10,000 humans has 6840 individuals with the blood type AA, 2860 individuals with blood type AB and 300 individuals with the blood type BB. If the next generation contained 25,000 individuals, how may individuals would have BB blood type, assuming the population is in Hardy-Weinberg equilibrium? Express as a whole number.A population of sea cucumbers from the maldives has the following allele frequencies for the tentacle colour gene; A= 0.7 and a=0.3. Using Hardy Weinberg equations and these allele frequencies, what are the expected genotype frequencies in the population?A population consists of 300 individuals with the following genotypes: AA – 100 Aa – 125 aa – 75 a. What are the values of p and q? b. Is the population in Hardy-Weinberg equilibrium? Explain.
- If a population is in Hardy-Weinberg equilibrium for the multiple alleles A+, A and a, whose frequencies are p= 0.60 for A+, q= 0.20 for A, and r = 0.20 for a, what percentage of the population is expected to be heterozygous?the frequency of allele a is 0.45 for a population inhardy-Weinberg equilibrium. What are the expectedfrequencies of genotypes AA, Aa, and aa?A large, random mating population is started with thefollowing proportion of individuals for the indicatedblood types:0.5 MM0.2 MN0.3 NNThis blood type gene is autosomal, and the M and Nalleles are codominant.a. Is this population at Hardy-Weinberg equilibrium?b. What will be the allele and genotype frequenciesafter one generation under the conditions assumedfor Hardy-Weinberg equilibrium?c. What will be the allele and genotype frequenciesafter two generations under the conditions assumedfor Hardy-Weinberg equilibrium?
- The frequency of the A1 allele is p = 0.4, and that of the A2 allele is q = 0.6. The observed genotype frequencies are as follows: f(A1A1) = 0.25 f(A1A2) = 0.36 f(A2A2) = 0.39 Is there a Hardy-Weinberg equilibrium in the population?Consider a population in which the D locus has two alleles, D and d, with f(D) = 0.6 and f(d) = 0.4. What are the genotypic frequencies expected under Hardy-Weinberg equilibrium?In a population with two alleles at the C locus (C and c), the frequency of the genotype cc is 0.14. Assuming that the C locus is at Hardy-Weinberg equilibrium in this population, what is the frequency of heterozygotes (Cc)? Round and report your answer to the second decimal place (0.00). Vour Answor: