A pendulum's angular position is given by 0 = 0.0300 cos(@t), where 0 is in radians and o = 8.48 rad/s. Find the period (in s) and length (in m) of the pendulum.periodSlength

Name: A pendulum's angular position is given by 0 = 0.0300 cos(@t), where 0
Uploaded: 2024-03-20T06:58:04.000Z
Channel: Bartleby
Description: A pendulum's angular position is given by 0 = 0.0300 cos(@t), where 0 is in radians and o = 8.48 rad/s. Find the period (in s) and length (in m) of the pendulum.periodSlength

Given, angular position of a pendulum, θ= 0.0300 cosωt ω= 8.48 rads

Answered: A pendulum's angular position is given…

Science

Physics

A pendulum's angular position is given by 0 = 0.0300 cos(@t), where 0 is in radians and w = 8.48 rad/s. Find the period (in s) and length (in m) of the pendulum. period length m

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter1: Units And Measurement

Section: Chapter Questions

Problem 81AP: Consider the equation s=s0+v0t+a0t2/2+j0t3/6+s0t4/24+ct5/120 , were s is a length and t is a time....

See similar textbooks

Similar questions

A Foucault pendulum is a simple device used to observe the rotation of the Earth. If the pendulum needs to have a period of 6.74 seconds, how long does the Foucault pendulum need to be (in meters)? Type your answer.
Ex. 59 The equation of S.H.M. is x 5 TC 10 at + Find the epoch, period and sin
The period T of a pendulum is the time it takes to move from one side to the other and back. A formula for the period is T=2πL32 where T is in seconds and L is in feet. Use 3.14 for π. Find the period of a pendulum of length 18 feet. (Type a decimal.)
Need some assistance with this. l = 1.95 mm. w= 1.89 mm. h= 5.82 m. Coordinates for Point A is A(2,2,2)m Coordinates for Point D is D(2.25,2.5,0)m Force F acts along EA, (Magnitude is 55N) Force P acTS along AD 4. What is BC as position vector rBC. ( rBCx, rBCy, rBCz ) 5. What is BC as unit vector uBC. (uBCx, uBCy, uBCz ) 6. What is the moment that F creates around B ? (MB) 7. What is the magnitude of the moment that F creates around axis BC. ( |MBC| )
ill BITE_LV ? 12:50 PM @マ 84% A physics.area.lv Question 4 of 7 What physical quantity is represented by symbol h in equation gt2 o Height of the device O Disc outer radius I = m: 2 - 1 2h o Rope length o Height of the pendulum fall Submit Answer く

QUESTION 5 1-The following equation refers to V-pendulum experiment: Y=-14X+15 and T4 Tª = (4лª L k/ g² )–(8 µªL / g² )d, where : TU L: length of the string (2 meters). T: pendulum periodic time d: distance between rods k: pendulum constant g: gravitational acceleration find the periodic time (T) if the distance equal (1) meter. 2.01 s 0.9 S 1.17 s 1 s
The period T of a pendulum is the time it takes to move from one side to the other and back. A formula for the period is T=2πL32 where T is in seconds and L is in feet. Use 3.14 for π. Find the period of a pendulum of length 50 feet.
What do I put for answers 1,2 and 3 with correct units?
The period T of a simple pendulum is the amount of timerequired for it to undergo one complete oscillation. If the lengthof the pendulum is L and the acceleration of gravity is g, then T isgiven by T = 2pLpgq. Find the powers p and q required for dimensional consistency.
Let A=6i-8), B=-8i+3 , and C=26i+19j . If aÀ+bB+C=0 .calculate the variables a and b.
The period T of a simple pendulum is the amount of time required for it to undergo one complete oscillation. If the length of the pendulum is L� and the acceleration of gravity is gg, then T� is given by T=2πLpgq Find the powers p� and q� required for dimensional consistency. Enter your answers numerically separated by a comma.
The period of a pendulum is the time it takes the pendulum to swing back and forth once. If the only dimensional quantities that the period depends on are the acceleration of gravity, g, and the length of the pendulum, l, what combination of g and l must the period be proportional to? (Acceleration has SI units of m/s^2)