A local five-star restaurant asks its patrons to fill out a quick satisfaction survey (is the patron satisfied or not) after their meal, and the restaurant claims that their satisfaction rating is 81%. Jennie, a food critic, would like to test this. She takes a sample of 150 patrons, and gets a 79.1% sample satisfaction rating. (a) Create a 99% confidence interval for the restaurant's true satisfaction rating. (Provide answers in decimal form, not percentage. Thus, 77.3% becomes 0.773. Round your answers to four decimal places, if needed.) (b) Based on this confidence interval, should Jennie reject the null hypothesis that the satisfaction rating is 81%? O Since the interval does not contain 81%, Jennie should reject the null hypothesis at a = 0.01. O Since the interval does not contain 81%, Jennie should not reject the null hypothesis at a = 0.01. O Since the interval contains 81%, Jennie should not reject the null hypothesis at a = 0.01. O Since the interval contains 81%, Jennie should reject the null hypothesis at a = 0.01.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
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A local five-star restaurant asks its patrons to fill out a quick satisfaction survey (is the patron satisfied or not) after their meal, and the restaurant claims that their satisfaction
rating is 81%. Jennie, a food critic, would like to test this. She takes a sample of 150 patrons, and gets a 79.1% sample satisfaction rating.
(a) Create a 99% confidence interval for the restaurant's true satisfaction rating. (Provide answers in decimal form, not percentage. Thus, 77.3% becomes 0.773. Round your
answers to four decimal places, if needed.)
(b) Based on this confidence interval, should Jennie reject the null hypothesis that the satisfaction rating is 81%?
O Since the interval does not contain 81%, Jennie should reject the null hypothesis at a = 0.01.
Since the interval does not contain 81%, Jennie should not reject the null hypothesis at a = 0.01.
Since the interval contains 81%, Jennie should not reject the null hypothesis at a = 0.01.
O Since the interval contains 81%, Jennie should reject the null hypothesis at a = 0.01.
Check
Transcribed Image Text:A local five-star restaurant asks its patrons to fill out a quick satisfaction survey (is the patron satisfied or not) after their meal, and the restaurant claims that their satisfaction rating is 81%. Jennie, a food critic, would like to test this. She takes a sample of 150 patrons, and gets a 79.1% sample satisfaction rating. (a) Create a 99% confidence interval for the restaurant's true satisfaction rating. (Provide answers in decimal form, not percentage. Thus, 77.3% becomes 0.773. Round your answers to four decimal places, if needed.) (b) Based on this confidence interval, should Jennie reject the null hypothesis that the satisfaction rating is 81%? O Since the interval does not contain 81%, Jennie should reject the null hypothesis at a = 0.01. Since the interval does not contain 81%, Jennie should not reject the null hypothesis at a = 0.01. Since the interval contains 81%, Jennie should not reject the null hypothesis at a = 0.01. O Since the interval contains 81%, Jennie should reject the null hypothesis at a = 0.01. Check
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