A hydroelectric plant has a head of 57 m and a water volumetric flow rate of 500 m/s. Determine the maximum power that the plant.can produce, the amount of electrical power that can be produced if the overall efficiency of the plant is 43% the energy that the plant will produce for operating hours of 8000h. (Take the density of water as 1000 kg/m). O a. Pmax = 280 MW, Pelec - 120.4 MW, E= 963.2 GWh O b. Pmax = 250 MW, Peec = 87.3 MW, E = 791 GWh O C. Pmax- 231 MW, Pelec = 101 MW, E - 766 GWh O d. Pmax = 331 MW, Peiec- 99.4 MW, E- 714 GWh O e. Pmax = 216 MW, Pelec = 98.9 MW, E = 791 GWh

A hydroelectric plant has a head of 57 m and a water volumetric flow rate of 500 m/s. Determine the maximum power that the plant.can produce, the amount of electrical power that can be produced if the overall efficiency of the plant is 43% the energy that the plant will produce for operating hours of 8000h. (Take the density of water as 1000 kg/m). O a. Pmax = 280 MW, Pelec - 120.4 MW, E= 963.2 GWh O b. Pmax = 250 MW, Peec = 87.3 MW, E = 791 GWh O C. Pmax- 231 MW, Pelec = 101 MW, E - 766 GWh O d. Pmax = 331 MW, Peiec- 99.4 MW, E- 714 GWh O e. Pmax = 216 MW, Pelec = 98.9 MW, E = 791 GWh

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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