A block of mass M = 10 kg is sitting on a surface inclined at angle 0 = 45°. Given that %3D the coefficient of static friction is equal to 0.5 between block and surface, what is the maximum force F that can be exerted without causing the block to slip?

A block of mass M = 10 kg is sitting on a surface inclined at angle 0 = 45°. Given that %3D the coefficient of static friction is equal to 0.5 between block and surface, what is the maximum force F that can be exerted without causing the block to slip?

Name: A block of mass M = 10 kg is sitting on a%3Dsurface inclined at angle
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Description: A block of mass M = 10 kg is sitting on a%3Dsurface inclined at angle 0 = 45°. Given thatthe coefficient of static friction is equal to0.5 between block and surface, what is themaximum force F that can be exertedwithout causing the block to slip?FMS

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter7: Dry Friction

Section: Chapter Questions

Problem 7.22P: A 1.1-kg disk A is placed on the inclined surface. The coefficient of static friction between the...

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