A bicycle, initially located Xo = 2.3 m at time t-0 seconds, has a velocity at time t given by%3Dv = 1.6 t3 + 5.6twith v in m/s and t in seconds. What is the position x (in meters) and the acceleration a (in m/s2) ofthe bicycle at time t?

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A bicycle, initially located xo = 2.3 m at time t=0 seconds, has a velocity at time t given by v = 1.6 t3 + 5.6 t with v in m/s and t in seconds. What is the position x (in meters) and the acceleration a (in m/s2) of the bicycle at time t?

A bicycle, initially located xo = 2.3 m at time t=0 seconds, has a velocity at time t given by v = 1.6 t3 + 5.6 t with v in m/s and t in seconds. What is the position x (in meters) and the acceleration a (in m/s2) of the bicycle at time t?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Relative Velocity

It is a measurement of an object with regards to the other object which is moving or stable or stationary. For example, if we are traveling in a bus and the bus is moving at speed of 50km/hr, then our speed is according to the nearby passenger on the bus is zero. According to them, we are not moving. But if one person standing on the ground or road observes us from outside of the bus, according to him we are moving at a speed of 50km/hr and the bus is also moving at a speed of 50km/hr. Now, the motion is recognized by the observer, it depends on a frame of reference or observer. This is motion called relative motion.

Question

A bicycle, initially located Xo = 2.3 m at time t-0 seconds, has a velocity at time t given by
%3D
v = 1.6 t3 + 5.6t
with v in m/s and t in seconds. What is the position x (in meters) and the acceleration a (in m/s2) of
the bicycle at time t?

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A bicycle, initially located xo = 2.3 m at time t=0 seconds, has a velocity at time t given by %3D v = 1.6 t3 + 5.6 t with v in m/s and t in seconds. What is the position x (in meters) and the acceleration a (in m/s-) of the bicycle at time t? O x= 0.53 t + 5.6 t2 + 2.3 a = 4.8 t2 + 5.6 O x = 0.4 t + 2.8 t2 + 2.3 a = 4.8 t2 + 2.3 O x = 4.8 t2 + 5.6 a = 0.4 t + 2.8t + 2.3 O x= 4.8 t2 + 2.3 a = 0.4 t + 2.8 t2 + 2.3 Ox = 0.4 t + 2.8 t2 + 2.3 a = 4,8 t2 + 5.6
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