A = B = C = | Now evaluate the indefinite integral. 2x² + 3x + 27 1 9) -dx = 3In(abs(x-3))-1/2ln(abs(x^2+9))+C Don't forget +C. 2x² + 3x + 27 (x − 3)(x² +9) A x - 3 + Bx + C x² +9
A = B = C = | Now evaluate the indefinite integral. 2x² + 3x + 27 1 9) -dx = 3In(abs(x-3))-1/2ln(abs(x^2+9))+C Don't forget +C. 2x² + 3x + 27 (x − 3)(x² +9) A x - 3 + Bx + C x² +9
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.4: Complex And Rational Zeros Of Polynomials
Problem 14E
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