(a-b)(c-d)(e-f)(g-h)(1) C=(j-k)(l-m)-C=C-CH3H₂, Raney Ni2. H₂O, H+1. CH3CH₂-MgBr2. H₂O, H+H₂, PdQuinolineBaSO41.032. H₂O-MgBrexcess HBrH₂O₂1. LIAIH42. H₂O, H+요CH3-CEC-CH₂CH₂CH3-CEC-H1.2. H₂O, H+H₂ (1 equivalent)PdNaBH4CH₂OHexcess Cl₂excess HCINaBH4, CH3OH (n-o)(p-q)(r-s)OH-Br??HNa??MgBr1.2. H:S:Br-CI

We know, the carbonyl compounds due to the electronegativity difference between carbon and oxygen…

Answered: (a-b) (c-d) (e-f) H₂, Raney Ni 1. -MgBr…

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(a-b) (c-d) (e-f) H₂, Raney Ni 1. -MgBr 2. H₂O, H+ 1. CH3CH₂-MgBr 1. 2. H₂O, H+ H₂ (1 equivalent) Pd NaBH4

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

(a-b)
(c-d)
(e-f)
(g-h)
(1) C=
(j-k)
(l-m)
-C=C-CH3
H₂, Raney Ni
2. H₂O, H+
1. CH3CH₂-MgBr
2. H₂O, H+
H₂, Pd
Quinoline
BaSO4
1.03
2. H₂O
-MgBr
excess HBr
H₂O₂
1. LIAIH4
2. H₂O, H+
요
CH3-CEC-CH₂CH₂CH3
-CEC-H
1.
2. H₂O, H+
H₂ (1 equivalent)
Pd
NaBH4
CH₂OH
excess Cl₂
excess HCI
NaBH4, CH3OH

(n-o)
(p-q)
(r-s)
OH
-Br
??
H
Na
??
MgBr
1.
2. H
:S:
Br
-CI

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