A 8.06 g sample of benzoic acid was dissolved in water to give 60.6 mL of solution. This solution was titrated with 0.250 M NaOH. What was the pH of the solution when the equivalence point was reached? Ka of benzoic acid is 6.3x10^-5 pH = ?
A 8.06 g sample of benzoic acid was dissolved in water to give 60.6 mL of solution. This solution was titrated with 0.250 M NaOH. What was the pH of the solution when the equivalence point was reached? Ka of benzoic acid is 6.3x10^-5 pH = ?
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter16: Acid-base Equilibria
Section: Chapter Questions
Problem 16.88QP: A 0.400-g sample of propionic acid was dissolved in water to give 50.0 mL of solution. This solution...
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Step 1: Given data
VIEWStep 2: Calculating the moles of benzoic acid
VIEWStep 3: Calculating the volume of NaOH needed for neutralization
VIEWStep 4: Calculating the concentration of conjugate base (benzoate ion)
VIEWStep 5: Constructing the ICE table and writing the Kb expression
VIEWStep 6: Calculating the concentrations at equilibrium
VIEWStep 7: Calculating the pH
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