A 1.000 mL aliquot of a solution containing Cu2t and Ni2+ is treated with 25.00 mL of a 0.05220 M EDTA solution. Thesolution is then back titrated with 0.02082 M Zn+ solution at a pH of 5. A volume of 20.42 mL of the Zn2t solution was neededto reach the xylenol orange end point. A 2.000 mL aliquot of the Cu2+ and Ni2+ solution is fed through an ion-exchange columnthat retains Ni²+. The Cu2+ that passed through the column is treated with 25.00 mL of 0.05220 M EDTA. This solutionrequired 15.92 mL of 0.02082 M Zn+ for back titration. The Ni2+ extracted from the column was treated witn 25.00 mL of0.05220 M EDTA.How many milliliters of 0.02082 M Zn2+ is required for the back titration of the Ni2+ solution?volume:mL

Given that : Volume of solution=1.000 mLVolume of EDTA = 25.00 mLMolarity of EDTA=0.05220 MMolarity…

A 1.000 mL aliquot of a solution containing Cu2+ and Ni2+ is treated with 25.00 mL of a 0.05220 M EDTA solution. The solution is then back titrated with 0.02082 M Zn2+ solution at a pH of 5. A volume of 20.42 mL of the Zn2t solution was needed to reach the xylenol orange end point. A 2.000 mL aliquot of the Cu2t and Ni2+ solution is fed through an ion-exchange column that retains Ni+. The Cu+ that passed through the column is treated with 25.00 mL of 0.05220 M EDTA. This solution required 15.92 mL of 0.02082 M Zn+ for back titration. The Ni2+ extracted from the column was treated witn 25.00 mL of 0.05220 M EDTA. How many milliliters of 0.02082 M Zn+ is required for the back titration of the Ni2+ solution? volume: mL

A 1.000 mL aliquot of a solution containing Cu2+ and Ni2+ is treated with 25.00 mL of a 0.05220 M EDTA solution. The solution is then back titrated with 0.02082 M Zn2+ solution at a pH of 5. A volume of 20.42 mL of the Zn2t solution was needed to reach the xylenol orange end point. A 2.000 mL aliquot of the Cu2t and Ni2+ solution is fed through an ion-exchange column that retains Ni+. The Cu+ that passed through the column is treated with 25.00 mL of 0.05220 M EDTA. This solution required 15.92 mL of 0.02082 M Zn+ for back titration. The Ni2+ extracted from the column was treated witn 25.00 mL of 0.05220 M EDTA. How many milliliters of 0.02082 M Zn+ is required for the back titration of the Ni2+ solution? volume: mL

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter14: Equilibria In Acid-base Solutions

Section: Chapter Questions

Problem 74QAP: Fifty cm3 of 1.000 M nitrous acid is titrated with 0.850 M NaOH. What is the pH of the solution (a)...

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