A 0.9134-g of KIO3 is dissolved in 500-mL distilled water. A 50.0-mL aliquot portion was run down into an Erlenmeyer flask and 2-g of KI and 2-mL of 6M HCl were added to it. Directly after, the solution was titrated with a 24.47-mL Na2S2O3 solution to a faint yellow solution. Starch TS was added to the resulting solution and the titration with the Na2S2O3 solution continued wherein an additional 1.33-mL was required to bring the blue color of the solution to disappear completely. MW: KIO3 = 214.0 g/mol ; Na2S2O3 = 158.1 g/mol Compute the M of the Na2S2O3 solution. 0.1047 M None of the choices 0.1107 M 0.09926 M

A 0.9134-g of KIO3 is dissolved in 500-mL distilled water. A 50.0-mL aliquot portion was run down into an Erlenmeyer flask and 2-g of KI and 2-mL of 6M HCl were added to it. Directly after, the solution was titrated with a 24.47-mL Na2S2O3 solution to a faint yellow solution. Starch TS was added to the resulting solution and the titration with the Na2S2O3 solution continued wherein an additional 1.33-mL was required to bring the blue color of the solution to disappear completely. MW: KIO3 = 214.0 g/mol ; Na2S2O3 = 158.1 g/mol Compute the M of the Na2S2O3 solution. 0.1047 M None of the choices 0.1107 M 0.09926 M

Macroscale and Microscale Organic Experiments

7th Edition

ISBN:9781305577190

Author:Kenneth L. Williamson, Katherine M. Masters

Publisher:Kenneth L. Williamson, Katherine M. Masters

Chapter7: Extraction

Section: Chapter Questions

Problem 1Q

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A 25 mL liquid bleach sample is diluted with water to 1000 mL in a bubble gel. 25 mL of the diluted sample is transferred to the flask with a pipette, excess KI is added to it, and thus OCl- ion turns into Cl- ion and I2 is formed. The released iodine is titrated with 0.09892 M Na2S2O3 using the starch reagent, and 8.96 mL is required for the endpoint. Find the % NaOCl (w/v; w/v) in the bleach sample. (Na=23 g/mol, O= 16 g/mol, Cl = 35.44 g/mol) (Warning: solving the necessary reaction equations by writing is necessary to see the stoichiometric relationship) A. 0.132% B. 0.264% C. 5.28% D. 10.56%
A 0.9000-g of KIO3 is dissolved in 500-mL distilled water. A 50.0-mL aliquot portion was run down into an Erlenmeyer flask and 2-g of KI and 2-mL of 6M HCl were added to it. Directly after, the solution was titrated with a 24.80-mL Na2S2O3 solution to a faint yellow solution. Starch TS was added to the resulting solution and the titration with the Na2S2O3 solution continued wherein an additional 1.33-mL was required to bring the blue color of the solution to disappear completely. MW: KIO3 = 214.0 g/mol ; Na2S2O3 = 158.1 g/mol Compute the N of the Na2S2O3 solution. None of the choices 0.09657 N 0.1075 N 0.1017 N
A 5.00 mL sample of filtered orange juice was treated with 50.00 mL of 0.01023 M I3 – to oxidize ascorbic acid to dehydroascorbic acid. After the oxidation was complete, excess I3 – was back-titrated with 13.82 mL of 0.07203 M Na2 S2O3 to starch indicator end point. What is the concentration of ascorbic acid in the orange juice? Report the concentration ascorbic acid in mg/100 mL. C6H8O6 + I3 – → C6H6O6 + 3I - + 2H+ I3 – + 2S2O3 2- → S4O6 2- + 3I2 Answer: 48.5 mg/100 mL
Approximately 6 mL of concentrated perchloric acid (72%) was transferred to a bottle and diluted with about 1.0 L of water. A sample containing 250.0 mg of primary standard sodium tetraborate (Na2B4O7 .10H2O, FW= 381.42 g/mol) was dissolved in 50.00 mL water and required 27.25 mL of the HClO4 solution to reach the methyl red end point. A 25.00 mL solution of an unknown NH3 sample required 13.24 mL of the HClO4 solution. Calculate the molarity of the NH3? Use the factor label method in answering.
Tea leaves were boiled and around 1.00 gram of caffeine were extracted using 175.0 ml of water. if three portions of 20.0 ml of dichloromethane were ised to extract the caffeine from the aqueous layer how may caffeine will be extracted by dichloromethane? Solubility of caffeine in water: 2.18 g per 100 ml water Solubility of caffeine in dichloromethane: 18.2 g per 100 ml dichloromethane
Approximately 6 mL of concentrated perchloric acid (72%) was transferred to a bottle and diluted with about 1.0L of water. A sample containing 250.0 mg of primary standard sodium tetraborate (NazB407 .10H2O, FW= 381.42 g/mol) was dissolved in 50.00 mL water and required 27.25 mL of the HCIO4 solution to reach the methyl red end point. A 25.00 mL solution of an unknown NH3 sample required 13.24 mL of the HCIO4 solution. Calculate the molarity of the NH3.
How many mg of Ag2SO4 dissolve in 0.3 M, 500 mL of Al2 (SO4) 3 solution? Compare this solubility with the solubility in purified water and 0.1 M Al2 (SO4) 3 solution. (Ksp = 1.10-5)
19- A 25 mL liquid bleach sample is diluted with water to 1000 mL in a bubble gel. 25 mL of the diluted sample is transferred to the flask with a pipette, excess KI is added to it, and thus OCl- ion turns into Cl- ion and I2 is formed. The released iodine is titrated with 0.09892 M Na2S2O3 using the starch reagent, and 8.96 mL is required for the endpoint. Find the % NaOCl (w/v; w/v) in the bleach sample. (Na=23 g/mol, O= 16 g/mol, Cl = 35,44 g/mol)
The ethyl acetate concentration in an alcoholic solution was determined by diluting a 10.00-mL sample to 100.00 mL. A 20.00-mL portion of the diluted solution was refluxed with 40.00 mL of 0.04672 M KOH:CH3COOC2H5 + OH- → CH3COO- + C2H5OHAfter cooling, the excess OH2 was back-titrated with 3.41 mL of 0.05042 M H2SO4. Calculate theamount of ethyl acetate (88.11 g/mol) in the original sample in grams
2.0 g of mixture involving Na3PO4, Na2HPO4 or NaH2PO4 or involving three of them. The solution is titrated with 16.5 mL of 0.5 M HCl to reach bromocresol green end point. The same solution is also titrated with 7.6 mL of 0.7 M NaOH to reach phenolphthalein end point. What is the composition of that mixture? What are the amounts of species (%) in the mixture (H:1.0078, O:15.99, Na: 22.98, P:30.974)?
A 5.00 mL sample of filtered orange juice was treated with 50.00 mL of 0.01019 M I3– to oxidize ascorbic acid to dehydroascorbic acid. After the oxidation was complete, excess I3– was back- titrated with 13.96 mL of 0.07125 M Na2S2O3 to starch indicator endpoint. What is the concentration of ascorbic acid (MM = 176.12) in the orange juice? Report the concentration ascorbic acid in mg/100mL. C6H8O6 + I3– → C6H6O6 + 3I- + 2H+ I3– + 2S2O32- → S4O62- + 3I2 42.89 % 40.85 % 27.34 % 82.51 %
A 5.00 mL sample of filtered orange juice was treated with 50.00 mL of 0.01019 M I3– to oxidize ascorbic acid to dehydroascorbic acid. After the oxidation was complete, excess I3– was back- titrated with 13.96 mL of 0.07125 M Na2S2O3 to starch indicator endpoint. What is the concentration of ascorbic acid (MM = 176.12) in the orange juice? Report the concentration ascorbic acid in mg/100mL. C6H8O6 + I3– → C6H6O6 + 3I- + 2H+ I3– + 2S2O32- → S4O62- + 3I2 A. 82.51 % B. 42.89 % C. 27.34 % D. 40.85 %