A 0.7026 g sample of an unknown acid requires 40.96 mL of 0.1158 M NaOH for neutralization to a phenolphthalein end point.  There are 1.22 mL of 0.1036 M HCl used for back-titration. How many moles of OH− are used? How many moles of H+ from HCl? How many moles of H+ are there in the solid acid? [moles H+ in solid acid = (moles OH− in NaOH soln. − moles H+ in HCl soln.] What is the molar mass of the unknown acid? (MM= grams of acid / moles of H+  )

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A: Molarity of Mg(OH)2 = 0.0075 M  Volume of solution = 500.0 mL

Q: Give detailed Solution with explanation needed..give answer both sub parts. I will give you upvote

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.