A 0.100 L solution is composed of 0.500 M (CH3)2NH and 0.500 M (CH3)2NH2Cl at 25 oC. What is the pH of the solution after 0.010 moles of KOH are added to the solution at the same temperature? You may assume there is no change in volume for the system. Enter your answer with two decimal places. At 25 degrees C: Kb for (CH3)2NH = 5.9 x 10-4

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.