_P4(s) + __Cl2(g) -->  __PCl5(g)             H°rxn = –1500 kJ In a reaction mixture of 0.22 g(P4) and 1.45 g(Cl2): The 0.22 grams of P4 are enough to form _______ mol       (PCl5)_______ LSTP (PCl5) The 1.45 grams of Cl2 are enough to form _______ mol      (PCl5)_______ LSTP (PCl5) The limiting reagent (LR) in the mixture is _______

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Chapter4: Stoichiometry
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__P4(s) + __Cl2(g) -->  __PCl5(g)             H°rxn = –1500 kJ

In a reaction mixture of 0.22 g(P4) and 1.45 g(Cl2):

The 0.22 grams of P4 are enough to form _______ mol       (PCl5)_______ LSTP (PCl5)

The 1.45 grams of Cl2 are enough to form _______ mol      (PCl5)_______ LSTP (PCl5)

The limiting reagent (LR) in the mixture is _______

The theoretical yield of PCl5 is _______ mol and _______ LSTP (liters at STP)

If 0.12 LSTP(PCl5) was isolated, the percent reaction yield is _______%

The most heat this reaction mixture can form is _______ kJ

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