8.a) A solution has a gravity of 90° Tw. Calculate its specific gravity and its gravity in degree Baume. b) An oil has a specific gravity at 15°/15°C of 0.81. Calculate its gravity in degree API and degree Baume. 9. The following reaction starts with 500 g of KMNO4. Using stoichiometric amounts of the other reactants, calculate the amounts of products formed. Illustrate the Law of Conservation of Mass. Mo203 + KMNO4 + H2SO4 = MoO3 + K2SO4 + MNSO4 + H2O 10. How many grams of chromic sulfide will be formed from 1.5 kg of chromic oxide according to the reaction? Cr203 + CS2 = Cr2S3 + CO2 %3D

Chemistry for Engineering Students
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ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
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please show step by step solution from the 3 questions given

8.a) A solution has a gravity of 90° Tw. Calculate its specific gravity and its gravity in degree Baume.
b) An oil has a specific gravity at 15°/15°C of 0.81. Calculate its gravity in degree API and degree Baume.
9. The following reaction starts with 500 g of KMNO4. Using stoichiometric amounts of the other reactants,
calculate the amounts of products formed. Illustrate the Law of Conservation of Mass.
Mo203 + KMNO4 + H2SO4 = MoO3 + K2SO4 + MNSO4 + H2O
10. How many grams of chromic sulfide will be formed from 1.5 kg of chromic oxide according to the
reaction?
Cr203 + CS2 = Cr2S3 + CO2
%3D
Transcribed Image Text:8.a) A solution has a gravity of 90° Tw. Calculate its specific gravity and its gravity in degree Baume. b) An oil has a specific gravity at 15°/15°C of 0.81. Calculate its gravity in degree API and degree Baume. 9. The following reaction starts with 500 g of KMNO4. Using stoichiometric amounts of the other reactants, calculate the amounts of products formed. Illustrate the Law of Conservation of Mass. Mo203 + KMNO4 + H2SO4 = MoO3 + K2SO4 + MNSO4 + H2O 10. How many grams of chromic sulfide will be formed from 1.5 kg of chromic oxide according to the reaction? Cr203 + CS2 = Cr2S3 + CO2 %3D
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