8. How many moles are in 16.4g of Lead (II) nitrate? Pb(NO3)2 + 2KI → Pbl2 + 2KNO3 9. How many moles of lead (II) iodide are formed from your moles of lead (II) nitrate in question 8? Pb(NO3)2 + 2KI → PbI2 + 2KNO3 10. How many grams are there in your moles of lead (II) iodide from question 9?

Appl Of Ms Excel In Analytical Chemistry
2nd Edition
ISBN:9781285686691
Author:Crouch
Publisher:Crouch
Chapter2: Basic Statistical Analysis With Excel
Section: Chapter Questions
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s New Ro.. v 12
A
B
I
U
Ev Ev E E E A-
Pb(NO3)2 + 2KI → Pbl, + 2KNO3
11. How many moles are in 28.5g of potassium iodide?
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
12. How many moles of lead (II) iodide are formed from your moles of potassium iodide in
question 11?
2
I
Hea
Pb(NO3)2 + 2KI → PbI, + 2KNO3
13. How many grams are in there in your moles of lead (II) iodide in question 12?
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
14. Which compound is your limiting reactant lead (II) nitrate or potassium iodide? (Hint: which
produced less product)
nglish (U.S.)
Text Predictions: On
90%
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SUE
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f9
F10
14
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Transcribed Image Text:activity - Saved to itslearning P Search Layout References Review View Help O Editing v s New Ro.. v 12 A B I U Ev Ev E E E A- Pb(NO3)2 + 2KI → Pbl, + 2KNO3 11. How many moles are in 28.5g of potassium iodide? Pb(NO3)2 + 2KI → PbI2 + 2KNO3 12. How many moles of lead (II) iodide are formed from your moles of potassium iodide in question 11? 2 I Hea Pb(NO3)2 + 2KI → PbI, + 2KNO3 13. How many grams are in there in your moles of lead (II) iodide in question 12? Pb(NO3)2 + 2KI → PbI2 + 2KNO3 14. Which compound is your limiting reactant lead (II) nitrate or potassium iodide? (Hint: which produced less product) nglish (U.S.) Text Predictions: On 90% earch SUE f8 f9 F10 14 (5 3 4 5 7 8 9.
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Get?Fileld-hNDLmdusbEmplc8ue%2laZn4otcFEREdCkEOBEgn%2bHNOn13v5HvafUMjlu77SxrKT
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O Editing v
w Ro... v 12
A^
U
ev Av A
=<而< 向 川<
3Ba+ N2 → BazN2
7. Which element is your limiting reactant Barium or Nitride? (Hint: which produced less
product)
Pb(NO3)2 + 2KI → PbI, + 2KNO3
8. How many moles are in 16.4g of Lead (II) nitrate?
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
9. How many moles of lead (II) iodide are formed from your moles of lead (II) nitrate in
question 8?
Pb(NO3)2 + 2KI → PbI, + 2KNO3
10. How many grams are there in your moles of lead (II) iodide from question 9?
Pb(NO3)2 + 2KI → PbI2 + 2KNO3
11. How many moles are in 28.5g of potassium iodide?
909
U.S.)
Text Predictions: On
ASUS
f10
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因
Transcribed Image Text:Hing.com Get?Fileld-hNDLmdusbEmplc8ue%2laZn4otcFEREdCkEOBEgn%2bHNOn13v5HvafUMjlu77SxrKT vity - Saved to itslearning P Search Layout References Review View Help O Editing v w Ro... v 12 A^ U ev Av A =<而< 向 川< 3Ba+ N2 → BazN2 7. Which element is your limiting reactant Barium or Nitride? (Hint: which produced less product) Pb(NO3)2 + 2KI → PbI, + 2KNO3 8. How many moles are in 16.4g of Lead (II) nitrate? Pb(NO3)2 + 2KI → PbI2 + 2KNO3 9. How many moles of lead (II) iodide are formed from your moles of lead (II) nitrate in question 8? Pb(NO3)2 + 2KI → PbI, + 2KNO3 10. How many grams are there in your moles of lead (II) iodide from question 9? Pb(NO3)2 + 2KI → PbI2 + 2KNO3 11. How many moles are in 28.5g of potassium iodide? 909 U.S.) Text Predictions: On ASUS f10 (12 f5 f6 f8 f9 & 6 7 8 因
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