8. A closed-loop system is shown in Figure Q8 below. Gain K, is positive. K 1 S² +85-9 Figure Q8 : system for Q 8 (a) Evaluate the close loop system's poles for (i) K = 0 (ii) K = 25 (iii) K→ ∞ (b) For what range of K will the transient part of the system response be oscillatory. Explain your answer. (c) Produce a fully-labelled root-locus plot for this system.

Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN:9781305632134
Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Chapter12: Power System Controls
Section: Chapter Questions
Problem 12.4P
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8. A closed-loop system is shown in Figure Q8 below. Gain K, is positive.
K
1
S² +85-9
Figure Q8 : system for Q 8
(a) Evaluate the close loop system's poles for
(i) K=0
(ii) K = 25
(iii) K→ ∞
(b) For what range of K will the transient part of the system response
be oscillatory. Explain your answer.
(c)
(d)
Produce a fully-labelled root-locus plot for this system.
Suppose the system input is unit step and K = 20. Determine the
resulting steady-state error. (Hint: use the limit value theorem).
(e) How you would eliminate stead-state error in a closed loop system
Transcribed Image Text:8. A closed-loop system is shown in Figure Q8 below. Gain K, is positive. K 1 S² +85-9 Figure Q8 : system for Q 8 (a) Evaluate the close loop system's poles for (i) K=0 (ii) K = 25 (iii) K→ ∞ (b) For what range of K will the transient part of the system response be oscillatory. Explain your answer. (c) (d) Produce a fully-labelled root-locus plot for this system. Suppose the system input is unit step and K = 20. Determine the resulting steady-state error. (Hint: use the limit value theorem). (e) How you would eliminate stead-state error in a closed loop system
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