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8 Add the half reactions together, cancel out any species that occur on both sides of the equation, and double-check for balanced atoms and charge. 2Cr(OH)3 + 10 OH + 3C1O + 3H₂O + 6e* → 2CrO4²- + 8H₂O + 6e + 3Cl +60H* The simplified equation becomes: ► 2Cr(OH)3 + 4OH + 3C1O → 2CrO4²- + 5H₂O + 3C1- This is balanced for all atoms and with respect to charge.

8 Add the half reactions together, cancel out any species that occur on both sides of the equation, and double-check for balanced atoms and charge. 2Cr(OH)3 + 10 OH + 3C1O + 3H₂O + 6e* → 2CrO4²- + 8H₂O + 6e + 3Cl +60H* The simplified equation becomes: ► 2Cr(OH)3 + 4OH + 3C1O → 2CrO4²- + 5H₂O + 3C1- This is balanced for all atoms and with respect to charge.

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 11QRT
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Demonstrate that step 8 of the example in basic solution is balanced with respect to both mass and charge. That is, for mass balance, show that the number of each type of atom is the same on the reactant and product side, and for charge balance, show that the total charge of all species is the same on the reactant and product side.
8 Add the half reactions together, cancel out any species that occur on both sides of the equation, and double-check for balanced atoms and charge. 2Cr(OH)3 + 10 OH + 3C1O+ 3H₂O + 6e* → 2CrO4²- + 8H₂O + 6e + 3Cl + 60H* The simplified equation becomes: ► 2Cr(OH)3 + 4OH + 3C10 ➜ 2CrO4²- + 5H₂O + 3C1- This is balanced for all atoms and with respect to charge.
Transcribed Image Text:8 Add the half reactions together, cancel out any species that occur on both sides of the equation, and double-check for balanced atoms and charge. 2Cr(OH)3 + 10 OH + 3C1O+ 3H₂O + 6e* → 2CrO4²- + 8H₂O + 6e + 3Cl + 60H* The simplified equation becomes: ► 2Cr(OH)3 + 4OH + 3C10 ➜ 2CrO4²- + 5H₂O + 3C1- This is balanced for all atoms and with respect to charge.
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