7:02 endo thermic d.. The melting of ice to form liquid water. 4. (1 pt) The specific heat of lead is 0.128 J/(g °C). If 34.2 g of lead, initially at 22.0°C, absorbs 3.689 kJ of heat, what will be the final temperature of the lead? A) 22.8 °C B821 °C B C) 865 °C D) 88.3 °C (2 pt) Write equations for the formation of the following from their respective elements in their standard states. Include AH from Appendix IIB. a. Fe2O3 (s) b. C3H7OH, isopropanol (1) 6. (1.5 pt) Given the following equations, calculate AH for: 3D + ½ A→ 5C AH (kJ/mol) A+6B-> 4C -2200 C+B-> D -175 AH = -2375 kJ/mol

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter8: Thermochemistry
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Problem 80QAP: Equal masses of liquid A, initially at 100C, and liquid B, initially at 50C, are combined in an...
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7:02
endo thermic
d.. The melting of ice to form liquid water.
4. (1 pt) The specific heat of lead is 0.128 J/(g °C). If 34.2 g of lead, initially at 22.0°C, absorbs 3.689 kJ of heat, what
will be the final temperature of the lead?
A) 22.8 °C
B821 °C
B
C) 865 °C
D) 88.3 °C
(2 pt) Write equations for the formation of the following from their respective elements in their standard states.
Include AH from Appendix IIB.
a. Fe2O3 (s)
b. C3H7OH, isopropanol (1)
6. (1.5 pt) Given the following equations, calculate AH for: 3D + ½ A→ 5C
AH (kJ/mol)
A+6B->
4C
-2200
C+B-> D
-175
AH = -2375 kJ/mol
Transcribed Image Text:7:02 endo thermic d.. The melting of ice to form liquid water. 4. (1 pt) The specific heat of lead is 0.128 J/(g °C). If 34.2 g of lead, initially at 22.0°C, absorbs 3.689 kJ of heat, what will be the final temperature of the lead? A) 22.8 °C B821 °C B C) 865 °C D) 88.3 °C (2 pt) Write equations for the formation of the following from their respective elements in their standard states. Include AH from Appendix IIB. a. Fe2O3 (s) b. C3H7OH, isopropanol (1) 6. (1.5 pt) Given the following equations, calculate AH for: 3D + ½ A→ 5C AH (kJ/mol) A+6B-> 4C -2200 C+B-> D -175 AH = -2375 kJ/mol
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