6. Calculate the enthalpy change of the following reaction between nitrogen gas and oxygen gas, given thermochemical equations (1). (2), (3). 2N2 50→2N₂O 2H₂ + O ENE 2H₂O N₂O + H₂O → 2HNO, Nau+ O2 + H₂HNO AH* = -572 kJ AH* = -77 kJ AH" --174 kJ

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6. Calculate the enthalpy change of the following reaction between nitrogen gas and oxygen gas,
given thermochemical equations (1), (2), (3).
2N+ 50 ➜ 2N₂0
(1)
(3)
N20
2H₂ + 0 → 2H₂O
N₂O + H₂O → 2HNO
O2 + H₂ → HNO
AH" = -572 kJ
AH* = -77 kJ
AH--174 kJ
Transcribed Image Text:6. Calculate the enthalpy change of the following reaction between nitrogen gas and oxygen gas, given thermochemical equations (1), (2), (3). 2N+ 50 ➜ 2N₂0 (1) (3) N20 2H₂ + 0 → 2H₂O N₂O + H₂O → 2HNO O2 + H₂ → HNO AH" = -572 kJ AH* = -77 kJ AH--174 kJ
2N2(g) + 502(g) → 2N2O5(g)
(1)
(2)
(3)
2H2(g) + O2(g) → 2H2O(l)
N205(g) + H2O(l) → 2HNO3(aq)
1/2N2(g) + O2(g) + 1/2H2(g) → HNO3(1)
AH° = -572 k
ΔΗ° = −77 k
AH = -174 k
Transcribed Image Text:2N2(g) + 502(g) → 2N2O5(g) (1) (2) (3) 2H2(g) + O2(g) → 2H2O(l) N205(g) + H2O(l) → 2HNO3(aq) 1/2N2(g) + O2(g) + 1/2H2(g) → HNO3(1) AH° = -572 k ΔΗ° = −77 k AH = -174 k
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