6. A connected graph with four edges and four vertices has two vertices of degree two. Show that a. G not Eulerian 3v EV: d(v) = 3 b. G is Eulerian G is regular

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 10E
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6. A connected graph with four edges and four vertices has two vertices of
degree two. Show that
a. G not Eulerian 3vEV: d(v) = 3
b. G is Eulerian G is regular
%3D
Transcribed Image Text:6. A connected graph with four edges and four vertices has two vertices of degree two. Show that a. G not Eulerian 3vEV: d(v) = 3 b. G is Eulerian G is regular %3D
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