6) The y phase in steel can transform into Pearlite and through diffusional processes. |
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- Q6 Use the Iron carbon diagram to find 4 of the following. ( 1- The range of solidification temp. (start to end of solidification) for cast iron with 3% C. 2- The solid and liquid percent for Cast Iron with 2.7%C at 1320 °C. 3- Draw the expected microstructure at room temp. for hypo-eutectoid steel with 0.7%C. 4- Draw the expected cooling curve from the melting point to room temp. for cast iron with 4.3%C. 5- The steps and the allotropy change for steel with 0.01%C.3- The limited solid solubility Binary phase diagram has many types of reactions like and....... 4- the Crystal Structure of y (Austenite) is J. (12-1394) at 2.44 wt% has fec. 5- The maximum solubility of carbon in austenite, 2 occurs at 1147° C while the maximum solubility "wt% 0.022 W+% of BCC is At 727 oC ******* 6-steel alloys classified according to carbon conctration into.....n) and (hough). which are 7- in polymer structure the long molecules are composed of structural entities called repeat & Cham the along successively repeated and 8-polymer classified according to their molecular structure into hul (30Mark)How much time in seconds is required for austenite to transform to 50% pearlite at 600°C?
- A molten Ag-Cu (20%) alloy is allowed to cool slowly from liquid phase till room temperature. Refer to Figure Ql and plot its cooling curve. Estimate % a just after it has solidified at 779 °C and at room temperature. Sketch its microstructure and find % eutectic.6- What is the critical cooling rate for hardening? Explain. Explain the effects of alloying elements on hardenability by showing them on the TTT (ZSD) diagram.Draw the iron carbon phase diagram and labeling all lines and areas. Then:- 1- find the melting point of cast iron with 2.2%C. 2- explain in detail the steps of solidification and transformation of cast iron with 3%C. 3- draw the expected microstructure of iron with 0.1%C ; 0.4%C; 0.83%C; 2%C; 4.3%C. 4-draw the cooling curve for hyper steel with 1.8%C. 5- find the percentage of liquid and solid for cast iron with 3.8%C at 1160 degree Celsius with the composition for each of them.
- How much time (in seconds) is required for austenite to transform to 50% bainite at 300°C?(11.10) Suppose that a steel of eutectoid composi- tion is cooled to 550°C (1020°F) from 760°C(1400°F) in less than 0.5 s and held at this temperature. (a) How long will it take for the austenite- to pearlite reaction to go to 50% comple- ton? To 100% completion? (b) Estimate the hardness of the alloy that has completely transformed to pearlite? 11.12) Briefly cite the differences between pearl- rp. bainite, and spheroidite relative to crostructure and mechanical properties?Q1/ In a homogeneous solidification process, assume molten metal solidifies into a spherical nucleus with a BCC structure. The given data are; lattice parameter (0.292 nm), the heat of fusion energy (1.85×10-9 J/m³), latent surface free energy (0.204 J/m²), critical radius (1-35 nm), equilibrium melting temperature (1516 K), and room temperature (27 °C). Calculate the following for this metal; (a) supercooling value temperature (b) activation tree energy (c) number of atoms in a nucleus of critical size.
- Q1: Austenitized 40 mm diameter 5140 alloy steel bar is quenched in agitated oil. Predict what is the Rockwell hardness of this bar will be at (a) its surface and (b) its center (c) What do you think about the difference in hardness number between the center and surface (d) Differentiate between hardness and hardenability (e) Rank the steels in the figure below from lowest to highest hardenability and explain why. 600- Bar diameter (mm) 100 80 60 40 20 0 300 0 Cooling rate at 700°C (°C/sec). -150 55 0 تنا 25 ------- 5 S 10 12.5 8 M-R L 1/2 34-R Agitated oil 15 20 ¼ ¾ Distance from quenched end. De (Jominy distance) 5,5 54 Car Bar diameter (in.) 0 25 mm. 1 in. Hardness (Rockwell C) Where (C = center, S = surface, M-R = mid-radius) 2828 292 65 60- 55- 50 45 40 35 30 25 20 15 10 0 J 10 5140 30 20 Distance from quenched end (mm) 4340 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 Distance from quenched end (sixteenths of an inch) 40 9840 4140 8640 50b) For the solidification of a metal, Tm =1000K with undercooling of 200K, calculate the rate of homogeneous nucleation in nuclei/m³/s. Neglect activation energy. Assume v=1o12/s and s'pd estimated as 1028/m³, AH=-1.26x10° J/m³, yLs= 0.16 J/m².What is a eutectic composition?