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50.0 mL of water at 40.5 °C is added to a calorimeter containing 50.0 mL of water at 1 After waiting for the system to equilibrate, the final temperature reached is 28.3 °C. Calcu heat capacity of the calorimeter. (sp_heat of water = 4.184 J/gx°C) Athot Atcold qhot qcold = qcal = 28.3 °C -40.5 °C -12.2 °C 28.3 °C -17.4 °C 10.9 °C mxsp_heat At (50.0 g)x(4.184 J/gx°C)x(-12.2 °C) -2550 J mxsp_heat At (50.0 g)x(4.184 J/gX°C)x(10.9 °C) 2280 J By rearranging the equation, qhot ' IV - (q cold +qcal), we can solve for q cal: qhot - qcold 2550 J - 2280 J 270 J 2701

50.0 mL of water at 40.5 °C is added to a calorimeter containing 50.0 mL of water at 1 After waiting for the system to equilibrate, the final temperature reached is 28.3 °C. Calcu heat capacity of the calorimeter. (sp_heat of water = 4.184 J/gx°C) Athot Atcold qhot qcold = qcal = 28.3 °C -40.5 °C -12.2 °C 28.3 °C -17.4 °C 10.9 °C mxsp_heat At (50.0 g)x(4.184 J/gx°C)x(-12.2 °C) -2550 J mxsp_heat At (50.0 g)x(4.184 J/gX°C)x(10.9 °C) 2280 J By rearranging the equation, qhot ' IV - (q cold +qcal), we can solve for q cal: qhot - qcold 2550 J - 2280 J 270 J 2701

Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
2nd Edition
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Steven S. Zumdahl, Susan A. Zumdahl
Chapter7: Chemical Energy
Section: Chapter Questions
Problem 62E: In a coffee-cup calorimeter, 1.60 g NH4NO3 is mixed with 75.0 g water at an initial temperature of...
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Hello, I just want to know if the work i attached for a calorimetry lab is correct,  is the qcal supposed to be positive in the reaction or is teh work shown incorrect

50.0 mL of water at 40.5 °C is added to a calorimeter containing 50.0 mL of water at 1 After waiting for the system to equilibrate, the final temperature reached is 28.3 °C. Calcu heat capacity of the calorimeter. (sp_heat of water = 4.184 J/gx°C) Athot Atcold qhot qcold = qcal = 28.3 °C -40.5 °C -12.2 °C 28.3 °C -17.4 °C 10.9 °C mxsp_heat At (50.0 g)x(4.184 J/gx°C)x(-12.2 °C) -2550 J mxsp_heat At (50.0 g)x(4.184 J/gX°C)x(10.9 °C) 2280 J By rearranging the equation, qhot ' IV - (q cold +qcal), we can solve for q cal: qhot - qcold 2550 J - 2280 J 270 J 2701
Transcribed Image Text:50.0 mL of water at 40.5 °C is added to a calorimeter containing 50.0 mL of water at 1 After waiting for the system to equilibrate, the final temperature reached is 28.3 °C. Calcu heat capacity of the calorimeter. (sp_heat of water = 4.184 J/gx°C) Athot Atcold qhot qcold = qcal = 28.3 °C -40.5 °C -12.2 °C 28.3 °C -17.4 °C 10.9 °C mxsp_heat At (50.0 g)x(4.184 J/gx°C)x(-12.2 °C) -2550 J mxsp_heat At (50.0 g)x(4.184 J/gX°C)x(10.9 °C) 2280 J By rearranging the equation, qhot ' IV - (q cold +qcal), we can solve for q cal: qhot - qcold 2550 J - 2280 J 270 J 2701
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