5.TRIHYBRID CROSS Determine all possible gametes of a cross between the gerbils and their fur color genes where hair shaft color is agouti (B) vs. black (b) which is physically caused by different deposition of melanin in the hair shaft; coat color pattern is solid (P) vs. piebald (p) and the modifier which is wild type (M) vs. modified (m) (affects melanin deposition). A trihybrid cross for all three traits would be BbPpMm x BbPpMm. Practice this in Punnett square.

5.TRIHYBRID CROSS Determine all possible gametes of a cross between the gerbils and their fur color genes where hair shaft color is agouti (B) vs. black (b) which is physically caused by different deposition of melanin in the hair shaft; coat color pattern is solid (P) vs. piebald (p) and the modifier which is wild type (M) vs. modified (m) (affects melanin deposition). A trihybrid cross for all three traits would be BbPpMm x BbPpMm. Practice this in Punnett square.

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Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter13: Genes, Chromosomes, And Human Genetics

Section: Chapter Questions

Problem 8TYK: Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene...

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2. Two unlinked loci effect mouse hair color. CC or Cc mice are agouti. Mice with genotype cc are albino because all pigment production and deposition of pigment in hair is blocked. At the second locus, the B allele (black agouti coat) is dominant to the b allele (brown agouti coat). A mouse with a black agouti coat is mated with an albino mouse of genotype bbcc. Half of the offspring are albino, one quarter are black agouti, and one quarter are brown agouti. What is the genotype of the black agouti parent?
13. In humans, red-green color blindness is recessive to normal sight. The gene for this trait is carried on the X chromosome (remember, Y is genetically inert). In each of the d following, give all types of offspring and their expected ratios: 2917039 (a) a colorblind man married to a heterozygous normal-sighted woman; pel (b) a color-blind man married to a homozygous normal-sighted woman; (c) a normal man married to a woman heterozygous for color blindness; wwpobos (d) a normal man married to a color-blind woman. b pla (O Who gedal 2010 QxWWSLO (5) tonaviy uwepod. Deba 44 ka, bal be
7. In rabbits, a locus involved in the control of coat colour may be occupied by any of fouralleles: Full colour (C), Sepia (ck), Cream (cd), or Albino (ca). A geneticist counted the numberof Full colour (C), Sepia (ck), Cream (cd) and Albino coat offspring resulting after crossesbetween Sepia (ck) and Cream (cd) coloured coated parents. The results were as follows.• Full colour (C): 152• Sepia (ck): 53• Cream (cd): 39• Albino (ca): 6Mendelian inheritance of this trait predicts that the ratio of Full colour (C) to Sepia (ck) to Cream(cd) to Albino (ca) should be 9:3:3:1. Do the experimental results support this mode ofinheritance?
17. Three recessive traits in aardwolf (a real animal) are stripe-less (s), dwarf (d), and fluffy mane (f). A stripe-less and fluffy female aardwolf mates with a dwarf male aardwolf to produce an F1 that is all WT (has stripes, normal size, and non-fluffy mane). When an F1 is test crossed to a fully recessive aardwolf, the following F2 are produced: Stripe-less, fluffy, normal sized 89 Striped, non-fluffy, dwarf 92 Stripe-less, non-fluffy, dwarf 1 Striped, fluffy, normal sized 2 11 13 19 20
6. In garden peas, round seeds ( R) are dominant over wrinkled (), yellow seeds ( Y) are dominant over green (y), purple flowers (A) are dominant over white (a) and tall plants (T) are dominant over short (t). Consider the following pea plants, and answer the questions below: Plant 1 = Rr Yy aa tt, Plant 2 = Rr Yy Aa Tt In a cross of Plant 1 x Plant 2, what proportion of progeny will: 6a. have the genotype Rr Yy aa tt? 6b. have the phenotype wrinkled, yellow seeds, white flowers, and short? 6c. have the dominant phenotype for all four characteristics? 6d. be pure breeding for seed shape?
5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous condition (RW) of red coat (R) and white coat (W) is roan, an example of codominance. (The roan coat contains both red and white fur because neither allele is dominant over the other). If a homozygous polled, white male is bred to a horned, red female, what will be the appearance of the F1 generation? Horned: r: Roan Coat: a. Possible genotypes for Polled condition Coat:_ ossible geno c. Male genotype: d. Female genotype: Male possible gametes Female possible gametes e. f. Genotypic Ratio: g. Phenotypic Ratio 5B, Breed two of the F1 generation to determine the possibilities in the F2 generation. Horned: a. Possible genotypes for Polled condition b. Possible genotypes for Red coat: White Coat:_ Roan Coat: c. Male genotype: d. Female genotype Male possible gametes Female possible gametes: f. Genotypic Ratio: g. Phenotypic Ratio
5A. In shorthorn cattle, the polled condition is dominant over horned. Also, the heterozygous condition (RW) of red coat (R) and white coat (W) is roan, an example of codominance. (The roan coat contains both red and white fur because neither allele is dominant over the other). If a homozygous polled, white male is bred to a horned, red female, what will be the appearance of the F1 generation? a. Possible genotypes for Polled condition: Horned: b. Possible genotypes for Red coat:White Coat: Roan Coat: c. Male genotype Male possible gametes: Female genotypeFemale possible gametes: e. f. Genotypic Ratio: g. Phenotypic Ratio:
2. In a summer squash, white fruit color (W) is dominant over yellow fruit (w) and disk-shaped fruit (D) is dominant over sphere-shaped fruit (d). If a squash plant true-breeding for white, disk-shaped fruit is crossed with a plant true-breeding for yellow, sphere-shaped fruit, what are the possible genotypes and phenotypes of their offspring. 3. In mice, the ability to run normally is a dominant trait. Mice with this trait are called running mice (R). The recessive trait causes mice to run in circles only. Mice with this trait are called waltzing mice (r). Hair color is also inherited in mice. Black hair (B) is dominant over brown hair (b).For each of the following problems, determine the parent genotypes, determine possible gametes then construct a Punnett Square to solve.a. Cross a heterozygous running, heterozygous black mouse with a homozygous running, homozygous black mouseb. Cross a homozygous running, homozygous black mouse with a heterozygous running brown mouse.
1. You are given a female F1 of unknown genotype. You cross the female fly to a homozygous male that has forked bristles and malformed eyes. The offspring of the cross is shown below: (Define symbols for your traits) Phenotype Forked bristles, normal eyes 752 Number Genotype Forked bristles, malformed 56 eyes Malformed eyes, normal bristles Normal eyes, normal bristles 820 64 a. What are the genotypes of the offspring? b. Based on the progeny, what were the genotypes of the F1 parents? What is the distance between for and mal?
23. In garden peas, tallness (T) is dominant to shortness (t) and axillary flowers (A) are dominant to terminal flowers (a). What are the expected genotypes and phenotypes of the offspring if a heterozygous tall, heterozygous axillary plant is crossed with a heterozygous tall, terminal plant? Give your answers in probabilities (%). a. What are the genotypes of the parents? b. Complete the dihybrid cross: C. What are the phenotype ratios?
1. The allele G for yellow stigma is completely dominant to green (g). Supposingtwo strains of autotetraploid plants are available and their genotypes are as follows:GGgg – in this plant the gene is close to the centromereGggg – in this plant the gene is far from the centromere If these two plants are crossed:a) provide the gametes that can be obtained from the two plants;b) provide the genotypic and phenotypic ratios of the offspring. 2. Consider the illustration below. Diagram the configuration you would observe at Anaphase I if crossing-over happens within the inversion. (IMAGE ATTACHED)
1-Show the results of a dihybrid cross for the F1 and F2 generation between P generation of a pea plant that is homozygous dominant for purple flower and yellow pea seed with another pea plant that is homozygous recessive for white flower and green pea seed. Clearly show the cross indicating BOTH genotype and phenotype for each generation. How many offspring in the F2 generation will have these phenotypes? 2-What is the probability of a woman who is a carrier for the blood disease hemophilia producing a son with hemophilia if she marries a man who does not have hemophilia? What is the probability of her daughters having hemophilia? Explain why the probability of getting this disease is different for sons versus daughters in this case. Your work should clearly indicated sex, genotype and phenotype (carrier or affected).